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3 years ago

13

HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP

1 answer:

Alex17521 [72]3 years ago

7 0

Answer:

<u>76 in²</u>

Step-by-step explanation:

<u>Area of the figure</u>

Area (top rectangle) + 2 x Area (bottom rectangle)
12 x (7 - 2) + 2 x 2 x 4
12 x 5 + 16
60 + 16
<u>76 in²</u>

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How do i solve this ?

sweet [91]

Answer:

m= - 3/6

Step-by-step explanation:

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3 years ago

Brainiest if correct or first<br> 1/2(6x+1/2)

Alexxx [7]

Step-by-step explanation:

1/2(6x+1/2)=0

3x+1/4=0

3X=-1/4

X=3(-1/4)

X=-3/4

OR

X=-.75

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3 years ago

Read 2 more answers

Evaluate -Z + 7.49 for Z = -7.1

luda_lava [24]

14.59

To solve, simply plug -7.1 into -Z. Since Z is negative in the equation, it will turn the Z that’s given to us into a negative. Since that Z is already negative, it will now become a positive since that’s what two negatives being multiplied make. This is what your problem will look like:

-(-7.1) + 7.49
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3 0

3 years ago

Match each series with the equivalent series written in sigma notation

PIT_PIT [208]

Answer:

$3 + 12 + 48 + 192 + 768 = \sum\limits^4_{n=0} 3 * 4^n$

$4 + 32 + 256 + 2048 + 16384 = \sum\limits^4_{n=0} 4 * 8^n$

$2 + 6 + 18 + 54 + 162 = \sum\limits^4_{n=0} 2* 3^n$

$3 + 15 + 75 + 375 + 1875 = \sum\limits^4_{n=0} 3* 5^n$

Step-by-step explanation:

Given

See attachment for complete question

Required

Match equivalent expressions

Solving (a):

$3 + 12 + 48 + 192 + 768$

The expression can be written as:

$3 \to 3*4^{0$ --- 0

$12 \to 3 * 4^{1$ ---- 1

$48 \to 3 * 4^{2$ --- 2

$192 \to 3 * 4^{3$ ---- 3

$768 \to 3 * 4^{4$ ---- 4

For the nth term, the expression is:

$Term = 3 * 4^{n$ ---- n

So, the summation is:

$3 + 12 + 48 + 192 + 768 = \sum\limits^4_{n=0} 3 * 4^n$

Solving (b):

$4 + 32 + 256 + 2048 + 16384$

The expression can be written as:

$4 \to 4 * 8^0$ --- 0

$32 \to 4 * 8^1$ ---- 1

$256 \to 4 * 8^2$ --- 2

$2048 \to 4 * 8^3$ ---- 3

$16384 \to 4 * 8^4$ ---- 4

For the nth term, the expression is:

$Term \to 4 * 8^n$ ---- n

So, the summation is:

$4 + 32 + 256 + 2048 + 16384 = \sum\limits^4_{n=0} 4 * 8^n$

Solving (c):

$2 + 6 + 18 + 54 + 162$

The expression can be written as:

$2 \to 2 * 3^0$ --- 0

$6 \to 2 * 3^1$ ---- 1

$18 \to 2 * 3^2$ --- 2

$54 \to 2 * 3^3$ ---- 3

$162 \to 2 * 3^4$ ---- 4

For the nth term, the expression is:

$Term \to 2 * 3^n$ ---- n

So, the summation is:

$2 + 6 + 18 + 54 + 162 = \sum\limits^4_{n=0} 2* 3^n$

Solving (d):

$3 + 15 + 75 + 375 + 1875$

The expression can be written as:

$3 \to 3 * 5^0$ --- 0

$15 \to 3 * 5^1$ ---- 1

$75 \to 3 * 5^2$ --- 2

$375 \to 3 * 5^3$ ---- 3

$1875 \to 3 * 5^4$ ---- 4

For the nth term, the expression is:

$Term \to 3 * 5^n$ ---- n

So, the summation is:

$3 + 15 + 75 + 375 + 1875 = \sum\limits^4_{n=0} 3* 5^n$

5 0

3 years ago

What is the slope of the line that passes through the points(7,-9) and (15,-29)?

Alex Ar [27]

(Y-Y1)/(X-X1)
(-9-(-29))/(7-15)
20/-8
-2 1/2
The slope is -2 1/2

3 0

3 years ago