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Galina-37 [17]
4 years ago
15

How to classify this conic ecwation 4x^2+9y^2-54y-63=0

Mathematics
1 answer:
MArishka [77]4 years ago
6 0
This looks like an ellipse.
Complete the square for y: 9(y²-6y-7)=9(y²-6y+9-9-7)=9((y-3)²-16).
Rewrite the equation:
4x²+9(y-3)²-144=0; 4x²/144+9(y-3)²/144=1; x²/36+(y-3)²/16=1.
Standard equation of an ellipse is (x-h)²/a²+(y-k)²/b²=1, where (h,k) is the origin or centre.
This is the equation of an ellipse with centre (0,3), a=6 and b=4 (semimajor and semiminor axes).
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What is 8/10 devided by 2/10
Alex777 [14]
The answer is 4. If you do the problem it would be like this




8/10 divided by 2/10, 8 divide 2 is 4. It would be 4/10 or 4.
3 0
3 years ago
Read 2 more answers
Please help due in 30 minutes!
Alexeev081 [22]

Answer:

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STEP-BY-STEP

8 0
3 years ago
Least to greatest 26/4, 6.45, 6 2/5, and 50/8
salantis [7]

Answer:

50/8 , 6\frac{2}{5} , 6.45 , 26/4

Step-by-step explanation:

The numbers are:

26/4 , 6.45 , 6\frac{2}{5} , 50/8

Converting the numbers to decimal form:

6.5 , 6.45 , 6.4 , 6.25

Arranging from least to greatest:

6.25 , 6.4 , 6.45 , 6.5

Converting back to initial form (in the least to greatest order):

50/8 , 6\frac{2}{5} , 6.45 , 26/4.

5 0
3 years ago
In a circle with an 8-inch radius, a central angle has a measure of 60°. How long is the segment joining the endpoints of the ar
sergij07 [2.7K]
The answer would be 8. An isosceles triangle is formed with each angle being 60, which means which side is 8.
5 0
4 years ago
Read 2 more answers
WILL GIVE BRAINLIEST
puteri [66]

Step-by-step explanation:

{EF}^{2} =   {EG}^{2}   -  {FG}^{2}  \\  \\  =  {8}^{2}   -  {6}^{2}  \\  \\  = 64 - 36 \\  \\  = 28 \\  \\  \therefore \:  {EF} =  \sqrt{28}  \\  \\ \therefore \:  {EF} =  2\sqrt{7}  \\  \\  \sin \: E =  \frac{FG }{EG}  =  \frac{6}{8}  =  \frac{3}{4}  \\  \\   \huge\red {\boxed{\therefore \:  \sin \: E = \frac{3}{4}} } \\\sec \: G =  \frac{ EG}{FG}  =  \frac{8}{6}  =  \frac{4}{3}  \\  \\   \huge\purple {\boxed{ \therefore \: \sec \: G = \frac{4}{3}}} \\\\\cot \: G =  \frac{ FG}{EF}  =  \frac{6}{2\sqrt 7}  =   \frac{3}{\sqrt 7}  \\  \\  =   \frac{3\times\sqrt 7 }{\sqrt 7\times\sqrt 7 }  \\  \\  =   \frac{3\sqrt 7 }{ 7 }  \\  \\   \huge\orange {\boxed{ \therefore \: \cot \: G =  \frac{3\sqrt 7 }{ 7 } }} \\\\

6 0
3 years ago
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