Ratios of Area of the two squares = 25:9
So then let the areas be A1 = 25A and A2 = 9A, A is common element
Side of the smaller area S2 = 30 meters
Area of the smaller square A2 = 30 x 30 = 900
We have area of smaller square as 9A = 900 => A = 100
Area of the large square = 25A = 25 x 100 = 2500.
Hence S1^2 = 2500 => S1 = 50 meters which is 20 meters longer than the
side of the smaller square.
Answer:
Minimum 8 at x=0, Maximum value: 24 at x=4
Step-by-step explanation:
Retrieving data from the original question:
![f(x)=x^{2}+8\:over\:[-1,4]](https://tex.z-dn.net/?f=f%28x%29%3Dx%5E%7B2%7D%2B8%5C%3Aover%5C%3A%5B-1%2C4%5D)
1) Calculating the first derivative
2) Now, let's work to find the critical points
Set this
0, belongs to the interval. Plug it in the original function
3) Making a table x, f(x) then compare
x| f(x)
-1 | f(-1)=9
0 | f(0)=8 Minimum
4 | f(4)=24 Maximum
4) The absolute maximum value is 24 at x=4 and the absolute minimum value is 8 at x=0.
Answer:
x . 1 . 3 . 5 . 7 . 9
y . 6 . 18 . 30 . 42 . 54
Step-by-step explanation:
X-values are the odd numbers
Y-values are the corresponding x-values multiplied by 6
Answer:
me dont know man why yall givin me this question
Step-by-step explanation:
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