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3 years ago

How.to express the sum 21/9 in a whole number and fractions

2 answers:

7 0

You have to divide 9 into 21. once you do that you get 2.3. the first number of the decimal will be the whole number and the second number will be the numerator of the fraction. your end product should be 2 3/9

zzz [600]3 years ago

5 0

Divide 21 by 9 that is 3 there is your whole number your fraction is 21/9 and your decimal would be 3.0

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Find the value of x<br> −8(x−6)=32

RUDIKE [14]

Answer:

x = 2

Step-by-step explanation:

-8(x-6) = 32 (distribute)

-8x+48 = 32 (subtract 48 from both sides)

-8x = -16 (divide)

x = 2

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3 years ago

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How to know how to solve properties of parallelograms

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Answer:

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3 years ago

Solve 15(5x−5)+3x=−9(13x+4) . Check your solution.

Iteru [2.4K]

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2 years ago

Which number will have the same result when rounded to the nearest ten or hundred A-97 B-118and5 C-179 D-5091

slamgirl [31]

Lets round it to the nearest ten
A 97 ====> 100
B 118 ===> 120
C 179 ===> 180
D 5091 ==> 5090
No result yet, lets round to the nearest hindred.
A 97 ====> 100
B 118 ===> 100
C 179 ===> 180
D 5091 ==> 5100
As we can see only A give the same result when we round it to the nearest hundred and nearest ten.

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3 years ago

The average expenditure on Valentine's Day was expected to be$100.89 (USA Today, February 13, 2006). Do male and femaleconsumers

stealth61 [152]

Answer:

(a) $62.16

(b) Male: $15.00

Female: $10.06

Confidence interval for female expenditure is ($49.18, $69.30)

Step-by-step explanation:

(a) Male expenditure

Sample mean = $135.67, sd=$35, n=40, Z=2.576

Population mean = sample mean - (Z×sd)/√n = 135.67 - (2.576×35)/√40 = 135.67 - 14.27 = $121.40

Female expenditure

Sample mean= $68.64, sd=$20, n=30, Z=2.576

Population mean = 68.64 - (2.576×20)/√30 = 68.64 - 9.40 = $59.24

$121.40 - $59.24 = $62.16

(b) Male: Error margin = (t-value × sd)/√n

Degree of freedom = n-1 = 40-1= 39. t-value corresponding to 39 degrees of freedom and 99% confidence level is 2.708

Error margin = (2.708×35)/√40 = 94.78/6.32 = $15.00

Female

Degrees of freedom = n-1 = 30-1 = 29. t-value is 2.756

Error margin = (2.756×20)/√30 = 55.12/5.48 = $10.06

Confidence Interval (CI) = (mean + or - error margin)

CI = 121.4 + 15.00 = $136.40

CI = 121.4 - 15.00 = $106.40

Confidence Interval is ($106.40, $136.40)

Female

CI = 59.24 + 10.06 = $69.30

CI = 59.24 - 10.06 = $49.18

Confidence Interval is ($49.18, $69.30)

7 0

3 years ago