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3 years ago

7

Line A passes through the points (220, 125) and (300, 75). Line B passes through the points (0, 0) and (30, 25). At what point d

o the lines intersect?

1 answer:

yanalaym [24]3 years ago

5 0

Answer:

No, Isiah is not correct. The GCF of the coefficients is 1, and there are no common variables among all three terms of the polynomial. 5b4 is a factor of -25a2b5 and -35b4, but not a3. Additionally, a2 is a factor of a3 and -25a2b5, but not -35b4

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(Math Help Quick Lots of points please thanks) 2

Alona [7]

Answer:

EY = 60

DW = 68

DE = 128

Step-by-step explanation:

Given

YW = 32
DZ = 64
FW = 68

As YW is the perpendicular bisector of EF, then EY = FY

FY = √(FW² - YW²) = √(68² - 32²) = 60

⇒ EY = 60

As WX is the perpendicular bisector of DF, then DW = FW

As FW = 68, then DW = 68

As WZ is the perpendicular bisector of DE, then DZ = EZ = 64

Therefore, DE = DZ + EZ = 64 + 64 = 128

8 0

3 years ago

Solve for Y <br><br> Y/5+7=9

Advocard [28]

Answer:

10

Step-by-step explanation:

<h2>—Math</h2>

y/5 + 7 = 9

y/5 = 9 – 7

y/5 = 2

y = 2 x 5

y = 10

<em>Follow </em><em>my </em><em>account^</em><em>^</em>

6 0

3 years ago

A quadrilateral has angles that measure 87°, 69°, and 104°. What is the measure of the fourth angle?

hodyreva [135]

The answer should be ................... 100

8 0

3 years ago

Read 2 more answers

Five companies (A, B, C, D, and E) that make elec- trical relays compete each year to be the sole sup- plier of relays to a majo

NNADVOKAT [17]

Answer:

a

$P(a | e') = 0.22$

$P(b | e') = 0.28$

$P(c | e') = 0.33$

b

$P(a | e' , d' , b') = 0.57$

Step-by-step explanation:

From the question we are told that

The probabilities are

Supplier chosen A B C

Probability P(a) = 0.20 P(b) = 0.25 P(c) = 0.15

D E

P(d) = 0.30 P(e) = 0.10

Generally the new probability of companies A being chosen as the sole supplier this year given that supplier E goes out of business is mathematically represented as below according to Bayes theorem

$P(a | e') = \frac{P (a \ and \ e')}{P(e')}$

$P(a | e') = \frac{P (a)}{P(e')}$

$P(a | e') = \frac{P (a)}{1- P(e)}$

=> $P(a | e') = \frac{ 0.20}{1- 0.10}$

=> $P(a | e') = 0.22$

Generally the new probability of companies B being chosen as the sole supplier this year given that supplier E goes out of business is mathematically represented as below according to Bayes theorem

$P(b | e') = \frac{P (b \ and \ e')}{P(e')}$

$P(b | e') = \frac{P (b)}{P(e')}$

$P(b | e') = \frac{P (b)}{1- P(e)}$

=> $P(b | e') = \frac{ 0.25}{1- 0.10}$

=> $P(b | e') = 0.28$

Generally the new probability of companies C being chosen as the sole supplier this year given that supplier E goes out of business is mathematically represented as below according to Bayes theorem

$P(c | e') = \frac{P (c \ and \ e')}{P(e')}$

$P(c | e') = \frac{P (c)}{P(e')}$

$P(c | e') = \frac{P (c)}{1- P(e)}$

=> $P(c | e') = \frac{ 0.15}{1- 0.10}$

=> $P(c | e') = 0.17$

Generally the new probability of companies D being chosen as the sole supplier this year given that supplier E goes out of business is mathematically represented as below according to Bayes theorem

$P(d | e') = \frac{P (d \ and \ e')}{P(e')}$

$P(d | e') = \frac{P (d)}{P(e')}$

$P(d | e') = \frac{P (d)}{1- P(e)}$

=> $P(d | e') = \frac{ 0.30}{1- 0.10}$

=> $P(c | e') = 0.33$

Generally the probability that B, D , E are not chosen this year is mathematically represented as

$P(N) = 1 - [P(e) +P(b) + P(d) ]$

=> $P(N) = 1 - [0.10 +0.25 +0.30 ]$

=> $P(N) = 0.35$

Generally the probability that A is chosen given that E , D , B are rejected this year is mathematically represented as

$P(a | e' , d' , b') = \frac{P(a)}{P(N)}$

=> $P(a | e' , d' , b') = \frac{0.20 }{0.35 }$

=> $P(a | e' , d' , b') = 0.57$

5 0

3 years ago

What is the undefined value of 3b^2+13b+4/b+4?

dmitriy555 [2]

Let f(b) = <span>3b^2+13b+4/b+4
</span>the domain of f is D = {b/ b+4#0} so b# - 4

so the undefined value of is when b = -4

8 0

3 years ago

Read 2 more answers