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erica [24]
3 years ago
10

Find 2 positive real numbers that differ by 1 and have a product of 1

Mathematics
1 answer:
velikii [3]3 years ago
6 0
A) x -y =1
B) x * y =1
B) y = 1/x

A) x -(1/x) = 1
Multiplying both sides by "x"
A) x^2 -1 = x
A) x^2 -x -1 = 0

Solving by the quadratic formula
x = 1.618 and
y = .618

Interestingly, the number 1.6180339... is called the "phi ratio" or the "golden ratio".
https://en.wikipedia.org/wiki/Golden_ratio




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2 years ago
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WITCHER [35]

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3 0
3 years ago
Read 2 more answers
What are the solutions of 4x2 - 8x +5 = 0 ?
MrRissso [65]

Answer:

x= {2+ i}/2 , {2- i}/2 = C

Step-by-step explanation:

4x² - 8x +5 = 0

using quadratic formula

x= {-b±√b²-4ac}/2a

x= [-(-8)±√(-8)²-4(4)(5)] /2x4 = [8±√64-80]/8= [8±√-16]/8 = {8±4 i}/8

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x=4 {2+ i}/8 , {2- i}/8

4 divides 8

x= {2+ i}/2 , {2- i}/2 = c

6 0
3 years ago
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