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3 years ago

Hi help what is 6a+17=2a-3

Mathematics

1 answer:

FrozenT [24]3 years ago

7 0

Answer:

a = -5

Step-by-step explanation:

6a + 20 = 2a

6a = 2a - 20

4a = - 20

a = -5

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Kurt is taking a roadtrip and has of his total distance left to travel. He plans to travel the remaining distance in 5 hours. Wh

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3 years ago

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A boat travels 438 km in 8 hours (with a constant speed). How far can it travel in 5 hours (with the same speed

Gre4nikov [31]

The distance that the boat can travel in one hour
=438km/8h
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2 years ago

What is the third quartile of this data set 20,21,24,25,28,29,35,37,39,42,44

dezoksy [38]

Answer:

The third quartile would be 39.

Step-by-step explanation:

• Since the numbers are already in order, the next step would be to find the median:

- The median is the middle number; found by ordering all data points and picking out the one in the middle.

The median would be 29.

• The first quartile, is denoted as Q1 and is the middle number that falls between the smallest value of the data set and the median.

The first quartile would be 24.

• The third quartile, is denoted as Q3 and is the median of the upper half of the data set.

The third quartile would be 39.

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6 0

3 years ago

Naval intelligence reports that 4 enemy vessels in a fleet of 17 are carrying nuclear weapons. If 9 vessels are randomly targete

icang [17]

Answer:

0.7588 = 75.88% probability that more than 1 vessel transporting nuclear weapons was destroyed

Step-by-step explanation:

The vessels are destroyed without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this question:

Fleet of 17 means that $N = 17$

4 are carrying nucleas weapons, which means that $k = 4$

9 are destroyed, which means that $n = 9$

What is the probability that more than 1 vessel transporting nuclear weapons was destroyed?

This is:

$P(X > 1) = 1 - P(X \leq 1)$

In which

$P(X \leq 1) = P(X = 0) + P(X = 1)$

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 0) = h(0,17,9,4) = \frac{C_{4,0}*C_{13,9}}{C_{17,9}} = 0.0294$

$P(X = 1) = h(1,17,9,4) = \frac{C_{4,1}*C_{13,8}}{C_{17,9}} = 0.2118$

Then

$P(X \leq 1) = P(X = 0) + P(X = 1) = 0.0294 + 0.2118 = 0.2412$

$P(X > 1) = 1 - P(X \leq 1) = 1 - 0.2412 = 0.7588$

0.7588 = 75.88% probability that more than 1 vessel transporting nuclear weapons was destroyed

8 0

2 years ago

The length of a rectangular plot is expressed as x²m and the breadth is xm if the area of the rectangular plot is 5832 sq cm the

Zanzabum

Answer:

442

Step-by-step explanation:

4 0

3 years ago