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3 years ago

Find the slope of the line through the pair of points. A (2,-3), P (2,9)

Mathematics

2 answers:

NNADVOKAT [17]3 years ago

6 0

The line is undefined

bagirrra123 [75]3 years ago

4 0

It is also called gradient.
y2 - y1 / x2 - x1
9 + 3 / 2 - 2
12 / 0 = undefined

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Which statement describes the inverse of m(x) = x^2 – 17x?

DochEvi [55]

Given:

The function is

$m(x)=x^2-17x$

To find:

The inverse of the given function.

Solution:

We have,

$m(x)=x^2-17x$

Substitute m(x)=y.

$y=x^2-17x$

Interchange x and y.

$x=y^2-17y$

Add square of half of coefficient of y , i.e., $\left(\dfrac{-17}{2}\right)^2$ on both sides,

$x+\left(\dfrac{-17}{2}\right)^2=y^2-17y+\left(\dfrac{-17}{2}\right)^2$

$x+\left(\dfrac{17}{2}\right)^2=y^2-17y+\left(\dfrac{17}{2}\right)^2$

$x+\left(\dfrac{17}{2}\right)^2=\left(y-\dfrac{17}{2}\right)^2$ $[\because (a-b)^2=a^2-2ab+b^2]$

Taking square root on both sides.

$\sqrt{x+\left(\dfrac{17}{2}\right)^2}=y-\dfrac{17}{2}$

Add $\dfrac{17}{2}$ on both sides.

$\sqrt{x+\left(\dfrac{17}{2}\right)^2}+\dfrac{17}{2}=y$

Substitute $y=m^{-1}(x)$ .

$m^{-1}(x)=\sqrt{x+(\dfrac{189}{4}})+\dfrac{17}{2}$

We know that, negative term inside the root is not real number. So,

$x+\left(\dfrac{17}{2}\right)^2\geq 0$

$x\geq -\left(\dfrac{17}{2}\right)^2$

Therefore, the restricted domain is $x\geq -\left(\dfrac{17}{2}\right)^2$ and the inverse function is $m^{-1}(x)=\sqrt{x+(\dfrac{189}{4}})+\dfrac{17}{2}$ .

Hence, option D is correct.

Note: In all the options square of $\dfrac{17}{2}$ is missing in restricted domain.

7 0

3 years ago

PLS HELP Complete the table so that the numbers in each column represent the coordinates of a point on the graph

Natasha2012 [34]

Answer:

1 is 1/2 5 is 2 1/2 and 7 would be 3 1/2

Step-by-step explanation:

4 0

3 years ago

For function of g,g(0)=1 and g(1)=5 assuming g is a linear function what is g(3)

lawyer [7]

Answer:

$g(3) = 13$

Step-by-step explanation:

Given

$g(0) = 1$

$g(1) = 5$

Required

Find g(3)

Since g(x) is a linear function, then:

$g(x) = mx + c$

For: $g(0) = 1$

$g(x) = mx + c$

$g(0) = m*0 + c$

$1 = 0 + c$

$1 = c$

$c = 1$

For: $g(1) = 5$

$g(x) = mx + c$

$g(1) = m * 1 + c$

$5 = m * 1 + c$

$5 = m + c$

Substitute $c = 1$

$5 = m + 1$

$m = 5 - 1$

$m =4$

So, the function is:

$g(x) = mx + c$

$g(x) = 4x + 1$

Calculate g(3)

$g(3) = 4*3 + 1$

$g(3) = 12 + 1$

$g(3) = 13$

3 0

3 years ago

A man travelled 3/8 of his journey by a rail 1/4 by a taxi 1/8 by and the remaining 2km on foot what is the length of his total

Burka [1]

The man travelled in different ways: by rail, by taxi, by ___ and by foot. I placed a blank there because there seems to be a missing word in the given problem above. For sample purposes, let's just assume that is travel by bus.

Since all of these travels are equal to 1 whole journey, you can express each travel as a fraction. When you add them up, the answer would be 1. So,

3/8 + 1/4 + 1/8 + x = 1

The variable x here denotes the fraction of his travel by foot. We are only given the exact distance travelled on foot which is 2 km. We have to find the fraction of the travel by foot to determine the length of the total distance travelled. Solving for x,

x = 1 - 3/8 - 1/4 - 1/8
x = 1/4

That means that the travel by foot comprises 1/4 of the whole journey. Thus,

Let total distance be D.

1.4*D = 2 km
D = 8 km

Therefore, the man travelled a total of 8 kilometers.

4 0

3 years ago

What is 1.38 as a fraction

slega [8]

1.38 as a fraction is 138/100 .

As a fraction, it can be reduced to lower terms.

138/100 = 69 / 50

7 0

3 years ago

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