Answer:
Thus, the equation hat correctly represents the number of ounces of beef stock,
, that the chef initially prepares.
⇒ ![\frac{s}{3}-8=34](https://tex.z-dn.net/?f=%5Cfrac%7Bs%7D%7B3%7D-8%3D34)
The total number of ounces of beef stock = 126
Step-by-step explanation:
Given:
Total ounces of beef stock = ![s](https://tex.z-dn.net/?f=s)
The chef divided the beef stock evenly into 3 smaller pans.
The chef then uses 8 ounces from one of the smaller pans.
Ounces of beef stock left in the smaller pan = 34
Solution:
Total ounces of beef stock = ![s](https://tex.z-dn.net/?f=s)
Ounces of beef stock in each smaller pan = ![\frac{s}{3}](https://tex.z-dn.net/?f=%5Cfrac%7Bs%7D%7B3%7D)
Ounces of beef stock used by the chef from the smaller pan = 8.
The ounces of beef stock left in the smaller pan will be given as:
⇒ ![\frac{s}{3}-8](https://tex.z-dn.net/?f=%5Cfrac%7Bs%7D%7B3%7D-8)
Ounces of beef stock remaining in smaller pan = 34
Thus, the equation hat correctly represents the number of ounces of beef stock,
, that the chef initially prepares.
⇒ ![\frac{s}{3}-8=34](https://tex.z-dn.net/?f=%5Cfrac%7Bs%7D%7B3%7D-8%3D34)
Solving for
.
Adding 8 both sides.
⇒ ![\frac{s}{3}-8+8=34+8](https://tex.z-dn.net/?f=%5Cfrac%7Bs%7D%7B3%7D-8%2B8%3D34%2B8)
⇒ ![\frac{s}{3}=42](https://tex.z-dn.net/?f=%5Cfrac%7Bs%7D%7B3%7D%3D42)
Multiplying both sides by 3.
⇒ ![3\times \frac{s}{3}=42(3)](https://tex.z-dn.net/?f=3%5Ctimes%20%5Cfrac%7Bs%7D%7B3%7D%3D42%283%29)
∴ ![s=126](https://tex.z-dn.net/?f=s%3D126)
Thus, total number of ounces of beef stock = 126