Answer:
<u>Part A</u> : 70 secondary oocytes will be formed.
<u>Part B</u> : 70 first polar bodies will be formed.
<u>Part C</u> : 70 ootids will be formed.
Explanation:
During oogenesis growth maturation of a single oogonium produces one primary oogonium.
the primary oogonium then undergoes meiosis -1 and produces one secondary oocyte and first polar body.
The secondary oocyte then undergoes meiosis - 2 and forms an ootid and second polar body.
The ootid then differentiates into the ovum.
As in the above scenario , 70 primary oocytes are present , they undergo meiosis-1 and produces 70 secondary oocytes and 70 first polar bodies. Hence answers of part A and B is 70.
As 70 secondary oocytes are formed , they undergo meiosis -2 and forms 70 ootids which then differentiate in 70 ovums.
Answer:
The third one
C6H12O6 + 6O2 → 6CO2 + 6H2O.
Explanation:
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1 = Birds, 2 = Mammals, 3 = Amphibians.
I took the test
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Enzymes in a reaction act as catalysts. They speed up the chemical reaction process.
The correct answer is d. both excitation and inhibition.
There is a process which is called summation and it refers to the process that determines whether or not an action potential (on postsynaptic neuron) will be generated by the combined effects of excitatory and inhibitory signals (from the presynaptic neurons). Depending on the sum total of inputs, summation may or may not reach the threshold voltage to trigger an action potential (firing of postsynaptic potential).
