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Georgia [21]
3 years ago
5

Vertical angles are congruent is that an example of a theorem

Mathematics
2 answers:
NISA [10]3 years ago
7 0
Whats the answers? I need them first


Pachacha [2.7K]3 years ago
3 0

Proof:

<span><span>∠1and∠2</span><span>∠1and∠2</span></span> form a linear pair, so by the Supplement Postulate, they are supplementary. That is,

<span><span>m∠1+m∠2=180°</span><span>m∠1+m∠2=180°</span></span>.

<span><span>∠2and∠3</span><span>∠2and∠3</span></span> form a linear pair also, so

<span><span>m∠2+m∠3=180°</span><span>m∠2+m∠3=180°</span></span>.

Subtracting <span><span>m∠2</span><span>m∠2</span></span> from both sides of both equations, we get

<span><span>m∠1=180°−m∠2=m∠3</span><span>m∠1=180°−m∠2=m∠3</span></span>.

Therefore,

<span><span>∠1≅∠3</span><span>∠1≅∠3</span></span>.

You can use a similar argument to prove that <span><span>∠2≅∠4</span><span>∠2≅∠4</span></span>.In the figure, 

<span><span>∠1≅∠3</span><span>∠1≅∠3</span></span> and <span><span>∠2≅∠4</span><span>∠2≅∠4</span></span>.

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<em>Additional</em><em> </em><em>information</em><em>:</em>

<em>Prime</em><em> </em><em>numbers</em><em> </em><em>are</em><em> </em><em>those</em><em> </em><em>numbers</em><em> </em><em>which</em><em> </em><em>can</em><em> </em><em>only</em><em> </em><em>be</em><em> </em><em>divided</em><em> </em><em>by</em><em> </em><em>itself</em><em> </em><em>.</em><em>for</em><em> </em><em>instance</em><em>:</em><em>1</em><em>,</em><em>2</em><em>,</em><em>3</em><em>,</em><em>5</em><em>,</em><em>7</em><em> </em><em>,</em><em>1</em><em>1</em><em>,</em><em>1</em><em>3</em><em> </em><em>etc</em><em>.</em>

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<em>Hope</em><em> </em><em>it </em><em>helps</em><em>.</em><em>.</em><em>.</em><em>.</em>

7 0
3 years ago
Given the set of ordered pairs: {(1,3), (2,7), (x,5), (6,4)}.
MrMuchimi

Answer:

2

Step-by-step explanation:

2 is a value of x that would not make the set a function because a function can't have multiple coordinates wit hthe same domain (x-coordinate). 2 is a domain that has already been used in the point (2,7). If this is used in (x,5), the point would become (2,5) and repeat a domain.

Note:

The x-coordinate could also be 1 or 6 because they have been used as domains as well.

Hope it helps!

8 0
3 years ago
100 points
lbvjy [14]

Answer:

  • 10

Step-by-step explanation:

IQR is the difference between Q3 and Q1

<u>According to the top box plot:</u>

  • Q1 = 4
  • Q3 = 14

<u>The IQR is:</u>

  • IQR = 14 - 4 = 10
4 0
3 years ago
Read 2 more answers
In triangle abc, the perimeter is 36, and ab=ac. line ad is perpendicular to bc at the point d, and triangle abd's perimeter is
Musya8 [376]
Let x=ab=ac, and y=bc, and z=ad.

Since the perimeter of the triangle abc is 36, you have:

Perimeter of abc = 36
ab + ac + bc = 36
x + x + y = 36
(eq. 1) 2x + y = 36

The triangle is isosceles (it has two sides with equal length: ab and ac). The line perpendicular to the third side (bc) from the opposite vertex (a), divides that third side into two equal halves: the point d is the middle point of bc. This is a property of isosceles triangles, which is easily shown by similarity.

Hence, we have that bd = dc = bc/2 = y/2 (remember we called bc = y).

The perimeter of the triangle abd is 30:

Permiter of abd = 30
ab + bd + ad = 30
x + y/2 + z =30
(eq. 2) 2x + y + 2z = 60

So, we have two equations on x, y and z:

(eq.1) 2x + y = 36
(eq.2) 2x + y + 2z = 60

Substitute 2x + y by 36 from (eq.1) in (eq.2):

(eq.2') 36 + 2z = 60

And solve for z:

36 + 2z = 60 => 2z = 60 - 36 => 2z = 24 => z = 12

The measure of ad is 12.

If you prefer a less algebraic reasoning:

- The perimeter of abd is half the perimeter of abc plus the length of ad (since you have "cut" the triangle abc in two halves to obtain the triangle abd).

- Then, ad is the difference between the perimeter of abd and half the perimeter of abc:

ad = 30 - (36/2) = 30 - 18 = 12
4 0
3 years ago
Read 2 more answers
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sattari [20]
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