All categories

3 years ago

Classify by degree of polynomial: 3x3 - 6x

Mathematics

1 answer:

e-lub [12.9K]3 years ago

7 0

Answer:

polynomial of degree 3

Step-by-step explanation:

Given

3x³ - 6x

The degree of a polynomial is given by the exponent of the term with the largest exponent.

In this case 3x³ has exponent 3 and - 6x has exponent 1

Thus this is a polynomial of degree 3

You might be interested in

Ln x + ln (x + 1) = ln 56

Leni [432]

Answer:

x=7

Step-by-step explanation:

ln x +ln(x+1)=ln 56

ln x(x+1)=ln 56

so x(x+1)=56

x^2+x-56=0

(x+8)(x-7)=0

x= -8 or x=7

and lnx,x>0

so x=7

3 0

4 years ago

Factor the following expression completely: 3x^2+9x+6

ArbitrLikvidat [17]

Answer:

The answer is 3(+1)(+2)

7 0

3 years ago

Read 2 more answers

Find the exact value of csc theta if tan theta = sqrt3 and the terminal side of theta is in Quadrant III.

WARRIOR [948]

Answer:

3rd option

Step-by-step explanation:

Using the identities

cot x = $\frac{1}{tanx}$

csc² x = 1 + cot² x

Given

tanθ = $\sqrt{3}$ , then cotθ = $\frac{1}{\sqrt{3} }$

csc²θ = 1 + ( $\frac{1}{\sqrt{3} }$ )² = 1 + $\frac{1}{3}$ = $\frac{4}{3}$

cscθ = ± $\sqrt{\frac{4}{3} }$ = ± $\frac{2}{\sqrt{3} }$

Since θ is in 3rd quadrant, then cscθ < 0

cscθ = - $\frac{2}{\sqrt{3} }$ × $\frac{\sqrt{3} }{\sqrt{3} }$ = - $\frac{2\sqrt{3} }{3}$

8 0

3 years ago

in the blanks below. Find the slope of the line passing through the points (-9, 2) and (9,2). slope:

user100 [1]

I will assume that we are trying to find the slope between (-9,2) and (9, 2)

The slope's equation ⇒ $\frac{y2-y1}{x2-x1}$

Let's set the variables:

(x1, y1) --> (-9, 2)

(x2, y2) --> (9, 2)

Now let's plug them in:

$Slope = \frac{2-2}{9--9} =\frac{0}{18} =0$

Thus the slope of the line is 0.

Hope that helps!

3 0

2 years ago

Add. Simplify your answer. 2/11 + 6/11

Margaret [11]

The answer is probably like 8/11

5 0

3 years ago

Read 2 more answers