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2 years ago

7

10 POINTS! Answer ASAP

2 answers:

Arte-miy333 [17]2 years ago

3 0

Answer:

angle ABD measures 25º

Alenkasestr [34]2 years ago

3 0

Answer:

angle 1 is the answer because it is congruent

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A cereal company is exploring new cylinder-shaped containers. Two possible containers are shown in the diagram.x is 6 and r=4.5

KatRina [158]

Answer:

Container $\rm X$ will have less label area than container $\rm Y$ by about $9\; \rm in$ .

Step-by-step explanation:

A rectangular sheet of paper can be rolled into a cylinder. Conversely, the lateral surface of a cylinder can be unrolled into a rectangle- without changing the area of that surface.

Indeed, the width of that rectangle will be the same as the height of the cylinder. On the other hand, the length of that rectangle should be exactly equal to the circumference of the circles on the top and the bottom of the cylinder. In other words, if a cylinder has a height of $h$ and a radius of $r$ at the top and the bottom, then its lateral surface can be unrolled into a rectangle of width $h$ and length $2\,\pi\, r$ .

Apply this reasoning to both cylinder $\mathrm{X}$ and $\rm Y$ :

For cylinder $\mathrm{X}$ , $h = 6\; \rm in$ while $r = 4.5\; \rm in$ . Therefore, when the lateral side of this cylinder is unrolled:

The width of the rectangle will be $6\; \rm in$ , while
The length of the rectangle will be $2 \, \pi \times 4.5\; \rm in = 9\, \pi\; \rm in$ .

That corresponds to a lateral surface area of $54\, \pi\; \rm in^2$ .

For cylinder $\rm Y$ , $h = 10.5\; \rm in$ while $r = 3\; \rm in$ . Similarly, when the lateral side of this cylinder is unrolled:

The width of the rectangle will be $10.5\; \rm in$ , while
The length of the rectangle will be $2\pi\times 3\; \rm in = 6\,\pi \; \rm in$ .

That corresponds to a lateral surface area of $63\,\pi \; \rm in^2$ .

Therefore, the lateral surface area of cylinder $\rm X$ is smaller than that of cylinder $\rm Y$ by $9\,\pi\; \rm in^2$ .

5 0

3 years ago

Help me please please

harina [27]

Answer:

a)

$EH = \sqrt{HG^2+EG^2} = \sqrt{4^2+6^2} = \sqrt{16+36} = \sqrt{52} = 2\sqrt{13}$

b)

EG² = GH*GF
EG² = 4*12
EG² = 48
EG = √48 = 4√3

3 0

2 years ago

Cedric opened a new gallon jug of milk and poured ¾ cup of milk for his mom, ½ cup milk for his little sister and 2 cups of milk

julia-pushkina [17]

Answer:

12 _3/4

Step-by-step explanation:

3/4 + 1/2 + 2 = 3_1/4

16 cups in a gallon

16-3_1/4

=12_3/4

7 0

3 years ago

To help you just Incase you need it

Lerok [7]

Thanks thank u so much

5 0

3 years ago

A sample of 30 distance scores measured in yards has a mean of 7, a variance of 16, and a standard deviation of 4. You want to c

Nikolay [14]

Answer:

21, 144, 12

Step-by-step explanation:

Given that a sample of 30 distance scores measured in yards has a mean of 7, a variance of 16, and a standard deviation of 4.

Let X be the distance in yard.

i.e. each entry of x is multiplied by 3.

New mean variance std devition would be

E(3x) = $3E(x) = 21$

Var (3x) = $3^2 Var(x) = 9(16) =144$

Std dev (3x) = $\sqrt{144 } =12$

Thus we find mean and std devition get multiplied by 3, variance is multiplied by 9

4 0

2 years ago