Answer:
The correct answer is - polyploidy.
Explanation:
Speciation can be two types allopatric and sympatric speciation. Sympatric speciation is the process of speciation is developing the new species that diverged from the common ancestral species while the ancestral and developed species both can share the same place or geological area. The main cause of such speciation is due to the change in their genetic level more than environmental conditions.
In this case, the frog's species show differences in their ploidy level as well as their mating call but polyploidy is the most likely the difference that evolved first rather than females call for mating.
Thus, the correct answer is - polyploidy.
For humans, the diploid chromosome number equation is 2n = 46 because humans have two sets of 23 chromosomes The diploid chromosome number varies by organism and ranges from 10 to 50 chromosomes per cell.
<h3>What is Mitosis?</h3>
Mitosis is a type of cell division that occurs in somatic or body cells. In mitosis, and a cell undergoes division to produce two daughter cells each with the same number of chromosome as the parent cells.
Mitosis produces diploid cells and diploid cells are cells that have the same number of chromosomes as the parent cell.
Thus, The diploid chromosome number varies by organism and ranges from 10 to 50 chromosomes per cell.
To learn more about chromosomes click here:
brainly.com/question/296477
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Carbon dioxide from the yeast comes from a process called fermentation. Fermentation is a cellular respiration process in cells that happens when oxygen is not present. If oxygen is present, the process is called aerobic respiration.
Answer:
0.7
Explanation:
Using Hardy-Weinberg equation of genetic variation being constant when disturbing factors such has mutation and others are removed.
p² + pq + q² = 1 and p + q = 1
where p² is the frequency of the homozygous dominant genotype (RR) and q² is the frequency of the homozygous recessive genotype (rr) and 2pq is the frequency of heterozygous genotype (Rr). p represent the frequency of "R" and q represent "g". since the coefficient against the green/green homozygote is 0.30 then
the fitness of the green/green homozygote = 1 - 0.3 = 0.7
