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3 years ago

7

Write the equation of a line that has a slope of -3 and goes through the point (5,7).

1 answer:

ss7ja [257]3 years ago

6 0

Answer:

The equation of the line would be D) y - 7 = -3(x -5)

Step-by-step explanation:

In order to find this, we must first start with the base form of point-slope form.

y - y1 = m(x - x1)

Now we put the slope in for m and the point in for (x1, y1)

y - 7 = -3(x - 5)

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3 years ago

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Complete the steps to solve the polynomial equation x3 – 21x = –20. According to the rational root theorem, which number is a po

jeka94

Answer:

Zeroes : 1, 4 and -5.

Potential roots: $\pm 1, \pm 2, \pm 4, \pm 5, \pm 10, \pm 20$ .

Step-by-step explanation:

The given equation is

$x^3-21x=-20$

It can be written as

$x^3+0x^2-21x+20=0$

Splitting the middle terms, we get

$x^3-x^2+x^2-x-20x+20=0$

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Splitting the middle terms, we get

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Using zero product property, we get

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Therefore, the zeroes of the equation are 1, 4 and -5.

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$x=\dfrac{\text{Factor of constant}}{\text{Factor of leading coefficient}}$

Constant = 20

Factors of constant ±1, ±2, ±4, ±5, ±10, ±20.

Leading coefficient= 1

Factors of leading coefficient ±1.

Therefore, the potential root of the polynomial are $\pm 1, \pm 2, \pm 4, \pm 5, \pm 10, \pm 20$ .

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