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Tresset [83]
3 years ago
14

How to make a linear equation perpendicular?

Mathematics
1 answer:
algol [13]3 years ago
4 0
The slopes of 2 perpendicular lines with be reciprocals with the opposite sign.
For example if you have the equation y=-5x+2, your slope is -5. In a line perpendicular to y=-5x+2, your slope would be 1/5. As for finding b in y=mx+b for your second equation, I would need more specific information.

Hope it helps!
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A company that produces fine crystal knows from experience that 13% of its goblets have cosmetic flaws and must be classified as
Kisachek [45]

Answer:

(a) The probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b) The probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c) The probability that at most five must be selected to find four that are not seconds is 0.9453.

Step-by-step explanation:

Let <em>X</em> = number of seconds in the batch.

The probability of the random variable <em>X</em> is, <em>p</em> = 0.31.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.

The probability mass function of <em>X</em> is:

P(X=x)={n\choose x}p^{x}(1-p)^{n-x};\ x=0,1,2,3...

(a)

Compute the probability that only one goblet is a second among six randomly selected goblets as follows:

P(X=1)={6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=6\times 0.13\times 0.4984\\=0.3888

Thus, the probability that only one goblet is a second among six randomly selected goblets is 0.3888.

(b)

Compute the probability that at least two goblet is a second among six randomly selected goblets as follows:

P (X ≥ 2) = 1 - P (X < 2)

              =1-{6\choose 0}0.13^{0}(1-0.13)^{6-0}-{6\choose 1}0.13^{1}(1-0.13)^{6-1}\\=1-0.4336+0.3888\\=0.1776

Thus, the probability that at least two goblet is a second among six randomly selected goblets is 0.1776.

(c)

If goblets are examined one by one then to find four that are not seconds we need to select either 4 goblets that are not seconds or 5 goblets including only 1 second.

P (4 not seconds) = P (X = 0; n = 4) + P (X = 1; n = 5)

                            ={4\choose 0}0.13^{0}(1-0.13)^{4-0}+{5\choose 1}0.13^{1}(1-0.13)^{5-1}\\=0.5729+0.3724\\=0.9453

Thus, the probability that at most five must be selected to find four that are not seconds is 0.9453.

8 0
3 years ago
X^(2)-3x+14 how many solutions does it have?
myrzilka [38]

Step by step:

x(2)−3x+14

=2x+−3x+14

Combine Like Terms:

=2x+−3x+14

=(2x+−3x)+(14)

=−x+14

Answer:

=−x+14

For some reason I could only find one... sorry!

Hope I could help thou! :)

 


6 0
3 years ago
Read 2 more answers
How do you solve for x a=2x+6xz
maksim [4K]

a = 2x + 6xz

a = x(2 + 6z) <em>factored out "x" on right side</em>

a/(2 + 6z) = x <em>divided both sides by (2 + 6z)</em>

Answer: x = \frac{a}{2 + 6z}

8 0
3 years ago
Write the equation of the line that passes through the points (4, -6) and (-2,3).
Butoxors [25]
In point slope form, the answer would be y = - 3/2 x it’s one fraction
5 0
3 years ago
Read 2 more answers
The difference between $500.02 - $79.3 add explanation if possible
liubo4ka [24]

Answer:

420.72

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
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