The equation y=0.02x+250 gives the weekly income y in terms of sales x.
Step-by-step explanation:
Given,
Weekly salary of real estate agent = $250
Commission rate = 2%
Let,
x be the sales per week.
y be the total weekly income.
Amount of commission = 2% of sales per week
Amount of commission = ![\frac{2}{100}*x](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B100%7D%2Ax)
Amount of commission = 0.02x
Total weekly income = Amount of commission + Weekly salary
![y=0.02x+250](https://tex.z-dn.net/?f=y%3D0.02x%2B250)
The equation y=0.02x+250 gives the weekly income y in terms of sales x.
Keywords: equation, percentage
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I believe the 3rd answer down if the information you provided is correct
Squaring the sum on the top, rules out 1 and 2 (not squaring the 7 only)
then 4 times the difference. so I believe 4 (x-1) on the bottom.
Answer:
Option D is the correct choice.
Step-by-step explanation:
We are provided angle of elevations of two artifacts buried beneath the ground and we are asked to find distance between these two elevations.
We will find distance between these elevations by taking the difference of two.
![35:\frac{4}{7}--8:\frac{2}{7}](https://tex.z-dn.net/?f=35%3A%5Cfrac%7B4%7D%7B7%7D--8%3A%5Cfrac%7B2%7D%7B7%7D)
![35:\frac{4}{7}+8:\frac{2}{7}=43:\frac{6}{7}](https://tex.z-dn.net/?f=35%3A%5Cfrac%7B4%7D%7B7%7D%2B8%3A%5Cfrac%7B2%7D%7B7%7D%3D43%3A%5Cfrac%7B6%7D%7B7%7D)
Since we know that distance is always positive so option A is incorrect.
Therefore, option D is the correct choice and distance between these two elevations is
.
Answer:
BC = 30
Step-by-step explanation:
If the three points are collinear, it means they lie on the same straight line.
Now B lies between A and C
By mathematical convention;
AC = AB + BC
This means;
48 = 2x + 2 + 3x + 6
48 = 5x + 8
48-8 = 5x
5x = 40
x = 40/5
x = 8
From the question BC = 3x + 6
Substitute the value of x; 3(8) + 6 = 24 + 6 = 30
To solve this, you have to know that the first derivative of a function is its slope. When an interval is increasing, it has a positive slope. Thus, we are trying to solve for when the first derivative of a function is positive/negative.
f(x)=2x^3+6x^2-18x+2
f'(x)=6x^2+12x-18
f'(x)=6(x^2+2x-3)
f'(x)=6(x+3)(x-1)
So the zeroes of f'(x) are at x=1, x=-3
Because there is no multiplicity, when the function passes a zero, he y value is changing signs.
Since f'(0)=-18, intervals -3<x<1 is decreasing(because -3<0<1)
Thus, every other portion of the graph is increasing.
Therefore, you get:
Increasing: (negative infinite, -3), (1, infinite)
Decreasing:(-3,1)