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bekas [8.4K]
2 years ago
11

Daniel worked for 2 1/3 hours and earned $18.20. How much would he make if he worked for 5 1/4 hours? Enter your answer in the b

ox.
Mathematics
2 answers:
Marat540 [252]2 years ago
8 0

Answer:

Daniel would make $40.95.

Step-by-step explanation:

We are given that,

The amount of money earned by Daniel after working for 2\dfrac{1}{3}=\dfrac{7}{3} hours = $18.20

Then, the amount of money earned by Daniel after working for 5\dfrac{1}{4}=\dfrac{21}{4} hour is,

Amount=\dfrac{18.20}{\dfrac{7}{3}}\times \dfrac{21}{4}\\\\Amount=\dfrac{18.20\times 3}{7}\times \dfrac{21}{4}\\\\Amount=\dfrac{54.6}{7}\times \dfrac{21}{4}\\\\Amount= 7.8\times 5.25\\\\Amount= \$ 40.95

<h3>Hence, Daniel would make $40.95.</h3>
Aleks04 [339]2 years ago
5 0
2 1/3hrs→ $18.20
1 hr→ $7.80
5 1/4hrs→ $7.80x5 1/4= $40.95
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Identify az of this sequence: 0.25, 0.5, 0.75, 1, 1.25. 1.5
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<h3><u>Question:</u></h3>

Identify a3 of this sequence: 0.25, 0.5, 0.75, 1, 1.25, 1.5,...a3=

<h3><u>Answer:</u></h3>

The third term of sequence is 0.75

a_3 = 0.75

<h3><u>Solution:</u></h3>

Given that, sequence is:

0.25, 0.5, 0.75, 1, 1.25. 1.5

Let us find the difference between terms

0.5 - 0.25 = 0.25\\\\0.75-0.5 = 0.25\\\\1.25-1=0.25\\\\1.5-1.25=0.25

This is a arithmetic sequence

Because the difference between any term and its immediately preceding term is always 0.25

In a arithmetic sequence,

a_1 = \text{ first term of sequnece }\\\\a_2 = \text{second term of sequnce }\\\\a_3 = \text{third term of sequnece }\\\\a_n = \text{ nth term of sequnce }

Thus, in the sequence 0.25, 0.5, 0.75, 1, 1.25. 1.5

a_3 = \text{ third term } = 0.75

Thus the third term of sequence is 0.75

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(2) (100, 300)

Step-by-step explanation:

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given the line AB with A(1,4) and B(-3,-1) is parallel to line CD with C(8,3) and D(x,-7), solve for the missing value of x.​
umka2103 [35]

Answer:

x = 0

Step-by-step explanation:

We can find the missing value by solving for the other points (graphically or algebraically). We would first find the line of Points A and B in order to find the parallel line that would help us find the coordinate point with the x-value.

1) Graph points A, B, and C.

2) Calculate the slope of points A and B by using the slope formula:

y2 - y1/x2 - x1.  

-1 - 4/-3 - 1....The slope is 5/4.

3) Write 4 = 5/4(x) + b

**We get 4 from the point A (1, 4)

Plug 1 into x and solve for 4 in order to get your y-intercept.

4 = 5/4(1) + b

4 = 5/4 +b

**If 1 = 4/4, then 4 = 16/4.

16/4 = 5/4 + b

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4) So our y-intercept is 2.75. We now have an equation of  y = 5/4x + 2.75 (graph it along with points A and B to see that it intersect both points.

5) Now we will use that line to find a line parallel to it. We know that if two lines have the same slope then they are parallel, so for the equation of the parallel line, we write: y = 5/4x + b so far.

6) We will find the y-intercept and use that to find the x-value of point D.

First we plug in the x and y values of point C to find the y-intercept

y = 5/4x + b --> 3 = 5/4(8) + b --> 3 = 40/4 + b --> 3 = 10 + b --> -7 = b

7) Now we have the equation of the line that is parallel to line AB: y = 5/4x -7

To find the missing value of x, plug the y-value of point D into the equation and solve for x.

--> -7 = 5/4x -7

--> x = 0

**You can double check this by graphing each point and both equations for the lines.

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