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borishaifa [10]
3 years ago
5

The Sun is v kilometers from the upper edge of the Earth's atmosphere and q kilometers from the surface of the Earth. Which of t

he following expressions always represents the distance between the Earth’s surface and the upper edge of the Earth's atmosphere?
Mathematics
2 answers:
horsena [70]3 years ago
6 0
The distance between the Earth's surface and the upper edge of the Earth's atmosphere would be Q - V.

The distance from the Sun to the Earth is Q. The distance from the Sun to the upper edge of the atmosphere is V. If you subtract V from Q, the remaining distance is that of the Earth's atmosphere.  Q - V = the atmosphere
Anarel [89]3 years ago
6 0

The correct answer is lv-ql

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azamat
$5 for reg
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3 years ago
2 1/8 x 2 6/9 <br><br> (Multiplying fractions)
IrinaVladis [17]

Answer:

17/6

Step-by-step explanation:

Start off with

2 1/8 * 2 6/9

Convert mixed number into improper fraction

17/8

reduce fraction with 3

17/8 * 2 * 2/3

Reduce numbers with GCD 2

17/4 * 2/3

Repeat

17/2 * 1/3

Multiply fractions

17*1/2*3

You then get...

17/6!

[Alternative forms: 2 5/6, 2.83]

5 0
3 years ago
Which equation has the solution x=6
Anni [7]

Answer:

B. x=6

move all terms to the left that don't contain x to the right side and solve.

8 0
2 years ago
Read 2 more answers
The original price of a jar of paint is$1.20 the store manager gets a 10 percent discount on orders of at least 50 jars of paint
sleet_krkn [62]

Answer:

$54

Step-by-step explanation:

50 * $1.20 = $60

Before the discount, 50 jars cost $60.

Since the discount rate is 10%, he will pay only 90% of the price since 100% - 10% = 90%.

90% of $60 =

= 90% * $60

= 0.9 * $60

= $54

4 0
3 years ago
A shipment To a warehouse consists of 4500 MP3 players the manager chooses a random sample of 50 MP3 players and finds that 7 ar
riadik2000 [5.3K]

Answer:

<u>630</u> MP3 players are likely to be defective.

Step-by-step explanation:

Given:

A shipment to a warehouse consists of 4500 MP3 players the manager chooses a random sample of 50 MP3 players and finds that 7 are defective.

Now, to find the MP3 players which are likely to be defective.

Let the defective MP3 players be x.

Total MP3 players = 4500.

In sample of 50 MP3 players 7 are defective.

Now, setting the proportion:

If, 50 is equivalent to 7.

Then, 4500 is equivalent to x.

Now, to solve using cross multiplication method:

\frac{50}{7} =\frac{4500}{x}

<em>By cross multiplying we get:</em>

<em />50x=31500<em />

<em>Dividing both sides by 50 we get:</em>

x=630.

Therefore, 630 MP3 players are likely to be defective.

5 0
3 years ago
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