I believe it would be the second option....
Number of weekend minutes used: x
Number of weekday minutes used: y
This month Nick was billed for 643 minutes:
(1) x+y=643
The charge for these minutes was $35.44
Telephone company charges $0.04 per minute for weekend calls (x)
and $0.08 per minute for calls made on weekdays (y)
(2) 0.04x+0.08y=35.44
We have a system of 2 equations and 2 unkowns:
(1) x+y=643
(2) 0.04x+0.08y=35.44
Using the method of substitution
Isolating x from the first equation:
(1) x+y-y=643-y
(3) x=643-y
Replacing x by 643-y in the second equation
(2) 0.04x+0.08y=35.44
0.04(643-y)+0.08y=35.44
25.72-0.04y+0.08y=35.44
0.04y+25.72=35.44
Solving for y:
0.04y+25.72-25.72=35.44-25.72
0.04y=9.72
Dividing both sides of the equation by 0.04:
0.04y/0.04=9.72/0.04
y=243
Replacing y by 243 in the equation (3)
(3) x=643-y
x=643-243
x=400
Answers:
The number of weekends minutes used was 400
The number of weekdays minutes used was 243
Answer: 2x(3+4)
Step-by-step explanation: 2x represents the one scoop of food twice a day, and 3+4 represents her 3 cats and 4 dogs.
What is the third quartile of the following data set<br><br>
24,20,35,39,28,42,25,29,44,21,37
strojnjashka [21]
First, arrange the data:
20, 21, 24, 25, 28, 29, 35, 37, 39, 42, 44
You can use the formula 3/4 multiplied by the number of data + 1 to find the position of the 3rd quartile.
so it's going to be 3/4 x (11+1) = 9th position
the number in 9th position is 39 so that's the 3rd quartile
Answer:
-2 -4 -6 -8
Step-by-step explanation:
I got the answer off of khan academy
