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tatyana61 [14]
3 years ago
11

A figure has a vertex at the point (-4, -6) the figure is dilated with the center at the Irgun with a scale factor of 5

Mathematics
1 answer:
IrinaK [193]3 years ago
4 0
You multiply the x and y by 5. You should get (-20, -30). Hopes this helps!
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The cost of a parking permit consists of a one-time administration fee plus a monthly fee. a permit purchased for 12 months cost
julsineya [31]

let

x--------> the monthly fee

y--------> the administration fee

we know that

660=y+12x --------> equation 1

810=y+15x --------> equation 2

Multiply by -1 equation 1

-660=-y-12x ------> equation 3

Adds equation 2 and equation 3

810=y+15x\\-660=-y-12x\\---------\\   810-660=15x-12x\\ 3x=150\\ x=50\ dollars

Find the value of y

660=y+12x\\ 660=y+12*50\\ y=660-600\\ y=60\ dollars

therefore

the answer is

the administration fee is equal to 60\ dollars

4 0
3 years ago
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The small submarine is at –1,320 feet in relation to sea level. The submarine needs to be 180 feet below sea level in 60 minutes
alexandr402 [8]

Answer:

The submarine needs to move up, so the rate the submarine needs to move is positive.

3 0
3 years ago
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4 Tan A/1-Tan^4=Tan2A + Sin2A​
Eva8 [605]

tan(2<em>A</em>) + sin(2<em>A</em>) = sin(2<em>A</em>)/cos(2<em>A</em>) + sin(2<em>A</em>)

• rewrite tan = sin/cos

… = 1/cos(2<em>A</em>) (sin(2<em>A</em>) + sin(2<em>A</em>) cos(2<em>A</em>))

• expand the functions of 2<em>A</em> using the double angle identities

… = 2/(2 cos²(<em>A</em>) - 1) (sin(<em>A</em>) cos(<em>A</em>) + sin(<em>A</em>) cos(<em>A</em>) (cos²(<em>A</em>) - sin²(<em>A</em>)))

• factor out sin(<em>A</em>) cos(<em>A</em>)

… = 2 sin(<em>A</em>) cos(<em>A</em>)/(2 cos²(<em>A</em>) - 1) (1 + cos²(<em>A</em>) - sin²(<em>A</em>))

• simplify the last factor using the Pythagorean identity, 1 - sin²(<em>A</em>) = cos²(<em>A</em>)

… = 2 sin(<em>A</em>) cos(<em>A</em>)/(2 cos²(<em>A</em>) - 1) (2 cos²(<em>A</em>))

• rearrange terms in the product

… = 2 sin(<em>A</em>) cos(<em>A</em>) (2 cos²(<em>A</em>))/(2 cos²(<em>A</em>) - 1)

• combine the factors of 2 in the numerator to get 4, and divide through the rightmost product by cos²(<em>A</em>)

… = 4 sin(<em>A</em>) cos(<em>A</em>) / (2 - 1/cos²(<em>A</em>))

• rewrite cos = 1/sec, i.e. sec = 1/cos

… = 4 sin(<em>A</em>) cos(<em>A</em>) / (2 - sec²(<em>A</em>))

• divide through again by cos²(<em>A</em>)

… = (4 sin(<em>A</em>)/cos(<em>A</em>)) / (2/cos²(<em>A</em>) - sec²(<em>A</em>)/cos²(<em>A</em>))

• rewrite sin/cos = tan and 1/cos = sec

… = 4 tan(<em>A</em>) / (2 sec²(<em>A</em>) - sec⁴(<em>A</em>))

• factor out sec²(<em>A</em>) in the denominator

… = 4 tan(<em>A</em>) / (sec²(<em>A</em>) (2 - sec²(<em>A</em>)))

• rewrite using the Pythagorean identity, sec²(<em>A</em>) = 1 + tan²(<em>A</em>)

… = 4 tan(<em>A</em>) / ((1 + tan²(<em>A</em>)) (2 - (1 + tan²(<em>A</em>))))

• simplify

… = 4 tan(<em>A</em>) / ((1 + tan²(<em>A</em>)) (1 - tan²(<em>A</em>)))

• condense the denominator as the difference of squares

… = 4 tan(<em>A</em>) / (1 - tan⁴(<em>A</em>))

(Note that some of these steps are optional or can be done simultaneously)

7 0
3 years ago
Solve for &lt; x &lt; 180degrees
Tamiku [17]

Option C: 90° is the value of x.

Explanation:

The given expression is 4+2 \sin x=14-8 \sin x for 0^{\circ} \leq x \leq 180^{\circ}

We need to solve the expression.

Thus, we have,

4+2 \sin x=14-8 \sin x

Subtracting both sides by 4, we have,

2 \sin x=10-8 \sin x

Adding both sides by 8 sin x, we get,

10 \sin x=10

Dividing both sides by 10, we have,

sin \ x=1

Taking sin^{-1} on both sides of the equation, we get,

x=sin^{-1}(1)

x=90^{\circ}

Thus, the value of x is 90°

Hence, Option C is the correct answer.

4 0
3 years ago
Cuanto es un <br> feet en ce centimetros
r-ruslan [8.4K]
How much is 1 foot in 1 centimeters?
First we need to know:
1 foot = 12 inches
1 inch = 2.54 cm
Those are the things that we need to know beforehand.

Then, we can start converting.
= 1 ft * (12 in / 1 ft) * (2.54 cm / 1in)
= 30.48 cm

So 1 foot is just equal to 30.48 cm
4 0
3 years ago
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