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luda_lava [24]
3 years ago
15

Complete the coordinate proof of the theorem. Given: A B C D is a square. Prove: The diagonals of A B C D are perpendicular. Art

: A square A B C D is graphed on a coordinate plane. The horizontal x-axis and vertical y-axis are solid. The vertex labeled as A lies on begin ordered pair 0 comma 0 end ordered pair. The vertex labeled as B lies on begin ordered pair a comma 0 end ordered pair. The vertices C and D are unlabeled. Diagonal A C and B D are drawn by dotted lines. Enter your answers in the boxes. The coordinates of square ABCD are A(0, 0) , B(a, 0) , C(, a), and D(0, ). The slope of AC⎯⎯⎯⎯⎯ , when simplified, is equal to . The slope of BD⎯⎯⎯⎯⎯, when simplified, is equal to −1 . The product of the slopes is equal to . Therefore, AC⎯⎯⎯⎯⎯ is perpendicular to BD⎯⎯⎯⎯⎯.
Mathematics
2 answers:
Alex787 [66]3 years ago
7 0

Since the square is on a quadrant plane and it is a square, the fact that the  lines cross in the center and start and stop in the corners allows you to tell that they are perpendicular.

So answer one is (B, D) 2 is (0, C) 3 is: 1


jeyben [28]3 years ago
3 0

Answer:


Step-by-step explanation:Complete the coordinate proof of the theorem.


Given: ABCD is a square.


Prove: The diagonals of ​ ABCD ​ are perpendicular.


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wlad13 [49]
A=2 (L+W)
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so a/2=L+W
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Find the quotient of 4.13 X 108 and 0.04 105. In two or more complete sentences, explain each step in your
Helen [10]

The quotient is 106.2

Step-by-step explanation:

Given the question as to find the quotient of  4.13×108 and 0.04×105 then

This can be written as;

\frac{4.13*108}{0.04*105}

multiplying the denominator by 100 to eliminate the decimals

\frac{4.13*108*100}{0.04*105*100} \\\\=\frac{413*108}{4*105} \\\\

Dividing both numerator value 108 by 4

\frac{413*108}{105*4} \\\\\frac{413*27}{105}

Dividing 27 and 105 by 3

\frac{413*27}{105} \\\\\\=\frac{413*9}{35}

Dividing 413 and 35 by 7

\frac{413*9}{35} \\\\\\\frac{59*9}{5} \\=531/5 =106.2

Learn More

Finding the quotient :brainly.com/question/10555114

Keywords: quotient, sentences, explain, calculations

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During the period of time that a local university takes phone-in registrations, calls come in at the rate of one every two minut
Marizza181 [45]

Answer:

The expected number of calls in one hour is 30.

The probability of three calls in five minutes is P(3) \approx0.2138

The probability of no calls in a five-minutes is P(0) \approx 0.0821

Step-by-step explanation:

We know that the calls come in at the rate of one every two minutes. To find the expected number of calls in one hour you need to:

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To find the probability of these events:

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We are going to use the Poisson distribution because is used when it is desirable to determine the probability of obtaining x occurrences over an interval of time like in this situation.

The Poisson probability function is defined by

P(x)=\frac{e^{-\mu}\mu^x}{x!}

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e = 2.71828

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Find μ

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Evaluate the formula for k = 3 and μ = 2.5

P(3)=\frac{e^{-2.5}2.5^3}{3!}\\P(3) \approx0.2138

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Evaluate the formula for  k = 0 and μ = 2.5

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