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3 years ago

What is the length of BC? ____ Units

Mathematics

2 answers:

Juli2301 [7.4K]3 years ago

8 0

X + 9 = 2x - 8
x - 2x = -8 - 9
-x = -17
x = 17

BC = x = 17

IRINA_888 [86]3 years ago

7 0

17

I hope this helps and have a wonderful day filled with joy!!

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1 yard is blank times as long as blank foot

8_murik_8 [283]

Answer:

Step-by-step explanation:

1 yard is three feet

5 0

3 years ago

A. Original Price: $16.20

Tom [10]

Answer:

The final price is $ 22.68 And Proportional constant is 1.4

Step-by-step explanation:

Given as :

The Original price = $ 16.20

The rate of increase = 40%

Let The final price = x

Now,

Final price after increase = initial price × ( 1 + $\frac{\textrm Rate}{100}$

Or. Final price after increase = $ 16.20 × ( 1 + $\frac{\textrm 40}{100}$

Or, Final price after increase = $ 16.20 × ( 1.4 )

∴ Final price after increase = $ 22.68

Now , Proportional constant = $\frac{22.68}{16.20}$

I.e Proportional constant = 1.4

Hence The final price is $ 22.68 And Proportional constant is 1.4 Answer

4 0

3 years ago

Is x = 6 a solution to the equation 5(x – 3) = x + 13?

deff fn [24]

Answer:

x=6 is not a solution

Step-by-step explanation:

We can substitute 6 as x to find out:

5(6-3)=6+13

first, because of PEMDAS we'll do 6-3

5(3)=6+13

multiply 5 by 3 and add 6 and 13

15=19

Since the statement is not true, that means that x=6 is not a solution

Hope this helps!

8 0

3 years ago

Find a − b when a = −7 and b = 11.

Mariana [72]

Answer:

-18

Explanation:

a - b

a = -7

b = 11

Insert -7 for 'a' and 11 for 'b'

-7 - 11

= -18

3 0

3 years ago

If logx27 + logy4 =5<br>and logx27 - logy4 =1<br>find x and y

Elanso [62]

Answer:

Hello,

I have reply too quick in comments (sorry)

Step-by-step explanation:

$\left\{\begin{array}{ccc}log_x (27)+log_y (4)=5\\log_x (27)-log_y (4)=1\\\end{array}\right.\\\\\\\left\{\begin{array}{ccc}2*log_x (27)=6\\2*log_y (4)=4\\\end{array}\right.\\\\\\\left\{\begin{array}{ccc}log_x (27)=3\\log_y (4)=2\\\end{array}\right.\\\\\\\left\{\begin{array}{ccc}x^{log_x (27)}=x^3\\y^{log_y (4)}=y^2\\\end{array}\right.\\\\\\\left\{\begin{array}{ccc}27=x^3\\4=y^2\\\end{array}\right.\\\\\\\left\{\begin{array}{ccc}x=3\\y=2\\\end{array}\right.\\\\$

5 0

2 years ago