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pshichka [43]
3 years ago
7

Multiply 11x +3 by 4. What is the product?

Mathematics
1 answer:
faltersainse [42]3 years ago
4 0

(11x+3)4

it will be 44x +12

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3 years ago
A meeting room has 60 chairs. There are 5 chairs at each table. How many tables are in the room?
kherson [118]

Answer:

12 Tables.

Step-by-step explanation:

There are many ways you can solve this with, here is the simplest.

Lets make it as a statement, IF 1 table has 5 chairs THEN how many X tables have 60 chairs.

Make it simplier:

1 Table = 5 Chairs

X Tables = 60 Chairs

using the cross multiplication method you will get

5X = 60

Divide by 5

X = 12

Which means that the room has 12 tables.

4 0
3 years ago
Read 2 more answers
Im stumped and timed.
VLD [36.1K]
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3 years ago
The students at Midtown Middle school sold flowers as a fundraiser in September and October. In October, they charged $1.50 for
MrRissso [65]
Part A: Let the September price be x, then
1.2x = 1.5
x = 1.5/1.2 = 1.25
Therefore, September price is $1.25

Part B: In September, they earned 0.4 * 1.25 * 900 = $450
In October, they earned 0.4 * 1.5 * 700 = $420
Therefore, they earned more money in September.
8 0
3 years ago
A model for the population p(t) in a suburb of a large city is given by the initial-value problem dp dt = p(10−1 − 10−7p), p(0)
irina1246 [14]

Answer:

T = 200 months

Step-by-step explanation:

Given the model to be

dp/dt = p(10-1-10-7p) where p(0) = 6000

dp/dt = p(-1-7p)

dp/dt = -p+7p²

But since P(0) = 6000

We plug this value into the equation

P = -6000+7(6000)²

P = -6000+252000000

P = 251994000. .limiting value

Differentiating dp/dt w.r.t p

dp/dt = -1+14p

dp'/dt = 14p-1

Plugging p(0) = 6000 into the above we have that

dp'/dt = 14(6000)-1

P' = 84000

Time population would be equal to 3/2 the limiting value

T = 3/2× 84000 = 126000

T = 25199400/126000

T = 199.99months

T = 200 months.

5 0
2 years ago
Read 2 more answers
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