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8_murik_8 [283]

3 years ago

8

Which of the following points lies on the line whose equation is y = 2x - 3? (0, 3) (1, -1) (-1, 4)

2 answers:

babunello [35]3 years ago

7 0

The answer would be (-1,4)

Andrej [43]3 years ago

3 0

The correct answer is (1, -1).

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recycled cds incorporated, offers a choice of 5 used cds for $26, with each additional cd costing $4. write a cost function for

Luda [366]

If $26 represents the cost of the 5 used CDs, than your formula would be "26+4x" ,x being the amount of extra CDs you purchase.

The number CDs minus 5 is our x value, because the first 5 are the used CDs bundled into the $26 group.

26+4(6-5)
26+4(1)
26+4
30

6 CDs would cost $30

3 0

3 years ago

Divide. 5892 ÷ 18 in fraction form.

umka2103 [35]

Answer: 327 1/3

Hope this helps! :)

3 0

3 years ago

Read 2 more answers

Solve this equation: 9x + 3 = 2(x - 4) - 3(2x + 5)

Ksju [112]

Answer: 5x

Step-by-step explanation:

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3 years ago

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soldi70 [24.7K]

Answer:

espero sirva qwq

Step-by-step explanation:

4= 0.56666666666

5=1.66666666667

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6 0

3 years ago

Sometimes a change of variable can be used to convert a differential equation y′=f(t,y) into a separable equation. One common ch

enot [183]

Answer:

$y=\frac{-7t^2+22t-7}{7t-22}$

Step-by-step explanation:

We are given that

Initial value problem

$y'=(t+y)^2-1$ , y(3)=4

Substitute the value $z=t+y$

When t=3 and y=4 then

z=3+4=7

$y'=z^2-1$

Differentiate z w.r.t t

Then, we get

$\frac{dz}{dt}=1+y'$

$z'=1+z^2-1=z^2$

$z^{-2}dz=dt$

Integrate on both sides

$-\frac{1}{z}dz=t+C$

$z=-\frac{1}{t+C}$

Substitute t=3 and z=7

Then, we get

$7=-\frac{1}{3+C}$

$21+7C=-1$

$7C=-1-21=-22$

$C=-\frac{22}{7}$

Substitute the value of C then we get

$z=-\frac{1}{t-\frac{22}{7}}$

$z=\frac{-7}{7t-22}$

$y=z-t$

$y=\frac{-7}{7t-22}-t$

$y=\frac{-7-7t^2+22t}{7t-22}$

$y=\frac{-7t^2+22t-7}{7t-22}$

8 0

4 years ago