In a family with 8 children, excluding multiple births, what is the probability of having 7 boys and 1 girl, in any order? a
ssume that a boy is as likely as a girl at each birth
1 answer:
There is a 7/8 chance there will be boys and a 1/8 chance there will be a girl
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Word form:
Two and seven hundred eighty-nine thousandths
Expanded form:
2
+ 0.7
+ 0.08
+ 0.009
Answer:
In the first expression:
(5^3)^-4 = 5^-12
Step-by-step explanation:
I think that the answer is negative 11 over 12
2. You simplified parenthesis on both sides
3. Subtracted 14 from -25 on right side
6. Divided each side by 9
Answer: 1/3
Step-by-step explanation:
5/15 divided both by 5 is 1/3
