Answer:
Answer = √(0.301 × 0.699 / 83) ≈ 0.050
A 68 percent confidence interval for the proportion of persons who work less than 40 hours per week is (0.251, 0.351), or equivalently (25.1%, 35.1%)
Step-by-step explanation:
√(0.301 × 0.699 / 83) ≈ 0.050
We have a large sample size of n = 83 respondents. Let p be the true proportion of persons who work less than 40 hours per week. A point estimate of p is because about 30.1 percent of the sample work less than 40 hours per week. We can estimate the standard deviation of as . A confidence interval is given by , then, a 68% confidence interval is , i.e., , i.e., (0.251, 0.351). is the value that satisfies that there is an area of 0.16 above this and under the standard normal curve.The standard error for a proportion is √(pq/n), where q=1−p.
Hope this answer helps you :)
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Mark brainliest
Answer:
$1016.4 - if this is just a simple multiplication question
Answer:
B.)
Step-by-step explanation:
baby :p
Answer:
19.74% of temperatures are between 12.9°C and 14.9°C
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:
What proportion of temperatures are between 12.9°C and 14.9°C?
This is the pvalue of Z when X = 14.9 subtracted by the pvalue of Z when X = 12.9.
X = 14.9
has a pvalue of 0.2420
X = 12.9
has a pvalue of 0.0446
0.2420 - 0.0446 = 0.1974
19.74% of temperatures are between 12.9°C and 14.9°C
