Question

Thank you for any help!

Answer 1

Answer:

D. No. (0, 0) satisfies $y>2x-1$ but does not satisfy $y\leq x^2-4$.

Step-by-step explanation:

We are given the following system of equations and we are to determine if (0, 0) is its solution or not:

$y\leq x^2-4$

$y>2x-1$

Substituting the given point $(0, 0)$ in both the equations to check if it satisfies them.

$y\leq x^2-4$ $\implies$ $0\leq (0)^2-4 \implies 0\leq -4$ - False

$y>2x-1 \implies 0 > 2(0)-1 \implies 0>-10$ - True

Therefore, the correct answer option is D. No. (0, 0) satisfies $y>2x-1$ but does not satisfy $y\leq x^2-4$.

Answer 2

The answer is D

0 is not less than or equal to -4, and in the second equation, 0 is greater than -1