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Phantasy [73]
3 years ago
7

What is the value of the function f(x) = 2x – 5 when x = 22? A17 B49 C105 D39

Mathematics
1 answer:
enyata [817]3 years ago
8 0
<span>f(x) = 2x – 5

</span><span>f(22) = 2(22) – 5 = 44 -5 = 39

answer

</span><span>D39</span>
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1 85/100

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If v = X + 4t, v is the velocity and X is the displacement, how to find X in terms of t?​
kobusy [5.1K]

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3 0
2 years ago
If an arrow is shot upward on Mars with a speed of 56 m/s, its height in meters t seconds later is given by y = 56t − 1.86t2.
Zina [86]

Answer: (a) (i)50.42 m/s (ii) 51.35 m/s (iii) 52.094 m/s (iv) 52.2614 m/s (v) 52.27814 m/s

(b) 54.14 m/s

Step-by-step explanation:

The average speed over the given time interval [a,b]: = \frac{y(b)-y(a)}{b-a}

Given: If an arrow is shot upward on Mars with a speed of 56 m/s, its height in meters t seconds later is given by y = 56t − 1.86t^2.

(a)

(i) average speed = \frac{y(2)-y(1)}{2-1}

=\frac{56(2)-1.86(2)^2-(56(1)-1.86(1)^2)}{1}

=50.42 m/s

(ii) average speed = \frac{y(1.5)-y(1)}{1.5-1}

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=51.35m/s

(iii) average speed = \frac{y(1.1)-y(1)}{1.1-1}

=\frac{56(1.1)-1.86(1.1)^2-(56(1)-1.86(1)^2)}{0.1}

=52.094m/s

(iv) average speed = \frac{y(1.01)-y(1)}{1.01-01}

=\frac{56(1.01)-1.86(1.01)^2-(56(1)-1.86(1)^2)}{0.01}

=52.2614&#10;m/s

(v) average speed = \frac{y(1.001)-y(1)}{1.001-01}

=\frac{56(1.001)-1.86(1.001)^2-(56(1)-1.86(1)^2)}{0.001}

=52.27814&#10;m/s

(b) y(1)=56(1)-1.86(1)^2

=56-1.86

= 54.14 m/s

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now

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