Answer:
33+12t−21t^2
Step-by-step explanation:
(2t-7)²-(5t-4)²
Use binomial theorem (a−b)^2 = a^2−2ab+b^2 to expand (2t-7)².
4t^2−28t+49−(5t-4)²
Use binomial theorem (a−b)^2 = a^2−2ab+b^2 to expand (5t-4)².
4t^2−28t+49−(25t^2−40t+16)
To find the opposite of 25t^2
−40t+16, find the opposite of each term.
4t^2−28t+49−25t^2−40t+16
Combine 4t^2 and −25t^2 to get −21t^2.
−21t^2−28t+49+40t−16
Combine −28t and 40t to get 12t.
−21t^2+12t+49−16
Subtract 16 from 49 to get 33.
−21t^2+12t+33
Swap terms to the left side.
33+12t−21t^2
I hope this helped!
A) they fornite a right angle and 2 acute angles(not 100% sure of what the Questions is asking)
B) they appear to form a triangle
C) the angles add up to 180 as they always do in all triangles
B)
(x+2)(x+8)(x+k)=x^3+9x^2+6x-16
(x^2+10x+16)(x+k)=x^3+9x^2+6x-16
x^3+10x^2+16x+kx^2+10kx+16k=x^3+9x^2+6x-16
kx^2+10kx+16k=-x^2-10x-16
k(x^2+10x+16)=-x^2-10x-16
k=(-x^2-10x-16)/(x^2+10x+16)
k=-1
so the width is (x-1)
Answer:
30 degrees
Step-by-step explanation:
The angles must add up to 180 degrees and the triangles have the same angles.
