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Llana [10]
3 years ago
5

The sale price of an item is four-fifths the original price of the item, x. Which statement explains why both 45x and 0.8x can f

ind the sale price of the item?
Mathematics
1 answer:
Inessa [10]3 years ago
5 0
The sale price is 4/5 of the original price...with x being the original price

4/5x
0.8x

these are the same because 4/5 = 0.8..its just in decimal form
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Which system of equations can be used to find the roots of the equation4x^5-12x^4+6x=5x^3-2x?
goblinko [34]

Answer:

y = 4x^5 - 12x^4 + 6x and

y = 5x^3 - 2x

Step-by-step explanation:

The system of equations that can be used to find the roots of the equation 4x^5-12x^4+6x=5x^3-2x are;

y = 4x^5 - 12x^4 + 6x and

y = 5x^3 - 2x

We simply formulate two equations by splitting the left and the right hand sides of the given equation.

The next step is to graph these two system of equations on the same graph in order to determine the solution(s) to the given original equation.

The roots of the given equation will be given by the points where these two equations will intersect.

The graph of these two equations is as shown in the attachment below;

The roots are thus;

x = 0 and x = 0.813

5 0
3 years ago
Y'=<img src="https://tex.z-dn.net/?f=%5Cfrac%7B-2x%2B2y%2B1%7D%7Bx-y%2B1%7D" id="TexFormula1" title="\frac{-2x+2y+1}{x-y+1}" alt
AlladinOne [14]

Answer:

see below

Step-by-step explanation:

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____ =   ______ – ___x^2 – ____y^2 – _____x + ______y

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8 0
3 years ago
What are all the primes of 52
AleksandrR [38]
<span>52 can be broken down to the following 
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</span>
6 0
3 years ago
Simplify:<br> i. (1 + tanA)2 + (1 – tanA)2
zalisa [80]

Answer:

hope this helps you a lot

have a great day

5 0
3 years ago
Read 2 more answers
The following histogram presents the amounts of silver (in parts per million) found in a sample of rocks. One rectangle from the
gladu [14]

Answer:

  • <u><em>The height of the missing rectangle is 0.15</em></u>

Explanation:

The image attached has the mentioned <em>histogram</em>.

Such histogram presents the relative frequencies for the clases [0,1], [1,2],[2,3], [4,5], and [5,6] Silver in ppm.

Only the rectangle for the class [3,4] is missing.

The height of each rectangle is the relative frequency of the corresponding class.

The relative frequencies must add 1, because each relative frequency is calculated dividing the absolute class frequency by the total number in the sample; hence, the sum of all the relative frequencies is equal to the total absolute class frequencies divided by the same number, yielding 1.

In consequence, you can sum all the known relative frequencies and subtract from 1 to get the missing relative frequency, which is the height of the missing rectangle.

<u>1. Sum of the known relative frequencies</u>:

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<u>2. Missing frequency</u>:

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<u>3. Conclusion</u>:

  • The height of the missing rectangle is 0.15

4 0
3 years ago
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