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S_A_V [24]
3 years ago
10

Solve the inequality |2x|+7>15

Mathematics
2 answers:
Radda [10]3 years ago
7 0
<span>|2x|+7>15  Set it to 0 and remove absolute value bars
x>4 or x<-4</span>
Oksana_A [137]3 years ago
4 0
Solved it by simple algebra so the x will be more than 4 x={567.....}
2x+7>15
2x>8
x>4
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i have 30 coins, all nickels, dimes and quarters, worth $4.60. there are two more dimes than quarters.. how many of each kind of
Oliga [24]

Answer:

Step-by-step explanation:

I have 30 coins, all nickels, dimes, and quarters, worth $4.60. There are two more dimes than quarters. How many of each kind of coin do I have.

..

let quarters be x

dimes = x+2

...

dimes + quarters = x+x+2=2x+2

...

nickels = 30-(2x+2)

...

5(30-(2x+2))+10(x+2)+25x=460

5(30-2x-2)+10x+20+25x=460

150-10x-10+10x+20+25x=460

160+25x=460

-160

25x=460-160

25x=300

/25

x=300/25

x=12 ---- quarters

x+2= 12+2=14 dimes

30-(2x+2)=4 nickels

...

check

4*5+14*10+12*25=20+140+300=460

4 0
2 years ago
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guapka [62]

Answer: q=\frac{\sqrt{81}}{16}

Step-by-step explanation:

16q^2-81=0\\16q^2=0+81=81\\16q=\sqrt{81} \\q=\frac{\sqrt{81}}{16}

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I NEED IT EXTREMELY FAST!!!!
pochemuha

Answer:

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Step-by-step explanation:

As you can see, the 3 turns into a six meaning it multiplied by 2. Apply this to 5.5 to get 11. The 2 is your scale factor.

Hope this helps,

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