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liq [111]
2 years ago
14

There are 180 students going on a class field trip. Of those students, 40% are boys. How many students on the field trip are boy

s?
Mathematics
2 answers:
MAXImum [283]2 years ago
5 0

Answer:

72 boys

Step-by-step explanation:

I got this right in a test hope this helps!!!

Rufina [12.5K]2 years ago
3 0

Answer:72 are boys.

Step-by-step explanation:

40%of 180 is 72.

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Plz help its hard for me
oksian1 [2.3K]
3.  Any number you choose between 7 and 3
4. Any number you choose below 8
6 0
3 years ago
Al precio de p dólares por unidad, se venden x unidades de cierto artículo al mes en el mercado con p=50-0.5x ¿Cuántas unidades
Ray Of Light [21]

Answer:

Se debe vender un mínimo mensual de 40 artículos para tener un ingreso mínimo de 1.200 dólares.

Step-by-step explanation:

De acuerdo con el enunciado, x es la cantidad mínima de artículos a un precio de p. Además, los ingresos totales deben ser de un mínimo de 1200. En consecuencia, tenemos el siguiente sistema de ecuaciones:

x \cdot p = 1200 (1)

p = 50-0.5\cdot x (2)

Aplicando (2) en (1), tenemos la siguiente ecuación polinómica:

x\cdot (50-0.5\cdot x) = 1200

50\cdot x -0.5\cdot x^{2} = 1200

0.5\cdot x^{2}-50\cdot x +1200 = 0 (3)

Por la Fórmula de la Cuadrática tenemos las raíces del polinomio:

x_{1} = 60, x_{2} = 40

De acuerdo con el resultado anterior, se debe vender un mínimo mensual de 40 artículos para tener un ingreso mínimo de 1.200 dólares.

3 0
3 years ago
The diameters of ball bearings are distributed normally. The mean diameter is 107 millimeters and the population standard deviat
tensa zangetsu [6.8K]

Answer:

0.6710

Step-by-step explanation:

The diameters of ball bearings are distributed normally. The mean diameter is 107 millimeters and the population standard deviation is 5 millimeters.

Find the probability that the diameter of a selected bearing is between 104 and 115 millimeters. Round your answer to four decimal places.

We solve using z score formula

z = (x-μ)/σ, where

x is the raw score

μ is the population mean = 107 mm

σ is the population standard deviation = 5 mm

For x = 104 mm

z = 104 - 107/5

z = -0.6

Probability value from Z-Table:

P(x = 104) = 0.27425

For x = 115 mm

z = 115 - 107/5

z = 1.6

Probability value from Z-Table:

P(x = 115) = 0.9452

The probability that the diameter of a selected bearing is between 104 and 115 millimeters is calculated as:

P(x = 115) - P(x = 104)

0.9452 - 0.27425

= 0.67095

Approximately = 0.6710

8 0
2 years ago
I think of number I add 14 to the number and multiply the result by 3 if my final answer is 51 what number did I think of​
erma4kov [3.2K]

Answer:

-1

Explanation:

Let the number be x.

Then the equation will be:

3(x+18) = 51

=> 3x + 54 = 51

=> 3x = 51 - 54

=> 3x = -3

=> x = -3/3

=> x = -1

So, the number you thought of is -1.

4 0
2 years ago
Read 2 more answers
An object launched straight up at a speed of 29.4 meters per second has a height, h, in meters of h , t seconds after the object
Nostrana [21]

Answer:

h = 44.06 meters (maximum height)

the time the object takes to complete this whole path is 6 seconds, this is why the time at which the object reaches its maximum height will between 0 and 6 seconds

Step-by-step explanation:

To solve this question, we need to first recognize that this is a constant acceleration problem, specifically, it can be thought of as a projectile motion problem.

Recall, the equations of motion:

1) v^2 - v_0^2 = 2a(s - s_0)\\2) s = v_0^2  + \frac{1}{2} at^2\\3) v = v_0 + at

What do we already know?

  • v_0 = 29.4 ms^-1
  • The launch is straight up
  • a = -9.81 ms^-2 this is the gravitational acceleration g
  • s_0 = 0 m, since our reference point is at s = 0, (the ground)

We can use use the Eq(1):

we know that when any object is launched up, at maximum height its velocity is going to be zero, v = 0 ms^-2

v^2 - v_0^2 = 2a(s - s_0)\\0^2 - (29.4)^2 = 2(-9.81)(s- 0)\\s = 44.06 m

this is the maximum height!

Why does t have to between zero and six?

We can answer this using a bit visualization, if you think about the second equation

s = v_0 t - \frac{1}{2}at^2\\ s = 29.4t - 4.905t^2

this is the equation of the whole trajectory that object makes.

and if you solve this by making s = 0, you will get the times at which the object was at the ground. the times will be 0s and 5.99s.

so the amount of time the object takes to go through this whole path is 6 seconds and this why the object will only reach its maximum height in between this time interval.

hope this helps :)

5 0
3 years ago
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