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liq [111]
3 years ago
14

There are 180 students going on a class field trip. Of those students, 40% are boys. How many students on the field trip are boy

s?
Mathematics
2 answers:
MAXImum [283]3 years ago
5 0

Answer:

72 boys

Step-by-step explanation:

I got this right in a test hope this helps!!!

Rufina [12.5K]3 years ago
3 0

Answer:72 are boys.

Step-by-step explanation:

40%of 180 is 72.

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I need help with this please, could you explain so I can understand better please
MA_775_DIABLO [31]

Answer:

<3 and <6 is Alternate interior angles.

<4 and <5 is Alternate interior angles.

<2 and <7 is Alternate exterior angles.

<3 and <7 is Corresponding angles.

Hope this helps. :)

8 0
3 years ago
If there bill was 58.65 and they gave a sever a 15% tip, how much did they pay altogether
masha68 [24]

Answer:

<u>$67.43 altogether</u>

Step-by-step explanation:

A 15% percent tip means 15% OF the bill.

15% of 58.65

0.15*58.65=8.7975

You can't really pay $8.7975, so you would round to the nearest one hundredth which is $8.78.

Now you add the $8.78 to $58.65 which will give you $67.43.

I hope that helps!


7 0
3 years ago
An article gave the following summary information for fracture strengths (MPa) of n = 196 ceramic bars fired in a particular kil
Oliga [24]

Answer:

54.80 MPa to 55.92 MPa

Step-by-step explanation:

Sample mean fracture strength (x) = 55.36 MPa

Sample standard deviation (s) = 3.99 MPa

Sample size (n) = 196.

The upper and lower bounds for a 95% confidence interval are given by:

U=x+1.960*\frac{s}{\sqrt{n}} \\L=x-1.960*\frac{s}{\sqrt{n}}

The upper and lower bounds of the confidence interval are;

U=55.36+1.960*\frac{3.99}{\sqrt{196}}\\U= 55.92\\L=55.36-1.960*\frac{3.99}{\sqrt{196}}\\L= 54.80\\

The 95% confidence interval for true average fracture strength is 54.80 MPa to 55.92 MPa

4 0
3 years ago
Solve:<br>3 = -2v - V<br>V=​
Y_Kistochka [10]

Answer:

V = −1

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

3=−2v−v

3=−2v+−v

3=(−2v+−v)(Combine Like Terms)

3=−3v

3=−3v

Step 2: Flip the equation.

−3v=3

Step 3: Divide both sides by -3.

<u>−3v</u>  = <u>3</u>

-3     -3

v=−1

4 0
3 years ago
Read 2 more answers
1) Suppose f(x) = x2 and g(x) = |x|. Then the composites (fog)(x) = |x|2 = x2 and (gof)(x) = |x2| = x2 are both differentiable a
Rufina [12.5K]

Answer:

This contradict of the chain rule.

Step-by-step explanation:

The given functions are

f(x)=x^2

g(x)=|x|

It is given that,

(f\circ g)(x)=|x|^2=x^2

(g\circ f)(x)=|x^2|=x^2

According to chin rule,

(f\circ g)(c)=f(g(c))=f'(g(c)g'(c)

It means, (f\circ g)(c) is differentiable if f(g(c)) and g(c) is differentiable at x=c.

Here g(x) is not differentiable at x=0 but both compositions are differentiable, which is a contradiction of the chain rule

3 0
3 years ago
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