“Equally likely outcomes in probability.
In some sample spaces, it is reasonable to estimate or assume that all outcomes in the space are equally likely (that they occur with equal probability). For example, when tossing an ordinary coin, one typically assumes that the outcomes "head" and "tail" are equally likely to occur.”
The value of x is 1. To solve this problem you have to setup the equation like this: 2(2x + 1) = 8x -2. This equation works because since Y is the midpoint, if you double YZ then you get XZ. From the equation you use distributive property to multiply 2 by everything within the parenthesis now the equation should look like this: 4x+2 = 8x -2. Now you can add 2 to both sides making the equation look like this: 4x + 4 = 8x. Then you subtract 4x from each side turning the equation into something like this: 4=4x then you divide by 4 on each side getting your answer: 1 = x.
Answer:
33.) = 4
34.) = 2
35.) = 6
36.) = 6
37.) = 91
38.) = 35
39.) = 4
40.) = 28
41.) = 18
42.) = (-6)
Step-by-step explanation:
<h3>33.)</h3>
(10 + 6) ÷ [(9 – 5) × (5 – 4)²]
(16) ÷ (4) × (1)²
16/4 = 4
Thus, The answer is 4
<h3>
34.)</h3>
(3² × 2) ÷ (5 + 8 – 5 + 1)
(9 × 2) ÷ (9)
18/9 = 2
Thus, The answer is 2
<h3>
35.)</h3>
6² ÷ {2 + 5 – [9 – (6 + 2)]}
6² ÷ [2 + 5 – (9 – 8)]
36 ÷ [2 + 5 – (1)]
36 ÷ 7 – 1
36/6 = 6
Thus, The answer is 6
<h3>
36.)</h3>
(3 × 3 × 2) ÷ (4 – 1)
18/3 = 6
Thus, The answer is 6
<h3>
37.)</h3>
4 × 3 × 10 – 4² – (10 + 3)
120 – 16 – 13
120 – 29 = 91
Thus, The answer is 91
<h3>
38.)</h3>
5 × [(22 – 1) × 2] ÷ (8 + 2 – 4)
5 × [(21) × 2] ÷ (6)
5 × 42 ÷ 6
5 × 7 = 35
Thus, The answer is 35
<h3>
39.)</h3>
-2 × 4 ÷ [2 + (-4) – (-4)] – 4
-8 ÷ (2 – 4 + 4) – 4
-8 ÷ 2 – 4
-8/-2 = 8/2 = 4
Thus, The answer is 4
<h3>
40.)</h3>
-4(-1 + 2) × 4 – 2 + (-1)
-4 × (1) × 4 – 2 – 1
(-4) × (-7) = 28
Thus, The answer is 28
<h3>
41.)</h3>
-3 – (-3 × 3) + 6 × 2
-3 – (-9) + 12
-3 + 9 + 12
6 + 12 = 18
Thus, The answer is 18
<h3>
42.)</h3>
6 – {3² + [3 × (-1)²]}
6 – [9 + (3 × 1)]
6 – (9 + 3)
6 – 12 = -6
Thus, The answer is (-6)
<u>-TheUnknownScientist 72</u>
Answer: (-2, 2) and (4, 8)
There are two solutions because the two functions cross each other twice.
Answer:
120
Step-by-step explanation:
