If they scored 5 times, they got 1 touchdown and 4 field goals.
Equation:
7 + 3 + 3 + 3 + 3 = 19.
Answer:
The maximum value of C is 68
Step-by-step explanation:
we have the following constraints
----> constraint A
----> constraint B
----> constraint C
----> constraint D
Find out the area of the feasible region, using a graphing tool
The vertices of the feasible region are
(0,0),(5,19),(5,0)
see the attached figure
To find out the maximum value of the objective function C, substitute the value of x and the value of y of each vertex in the objective function and then compare the results

For (0,0) -----> 
For (5,19) -----> 
For (5,0) -----> 
therefore
The maximum value of C is 68
Firstly, we will draw diagram
we will draw line qq'
which will make mqq'n as parallelogram
and we know that opposite sides of parallelograms are always equal
so, we get

we are given
mq=42
so,

we can see that q' lies on np
so, we can write as

we are given
np=112
so, we can plug these values



now, we can see that
triangle qpq' forms isosceles triangle
so, we get


so,
............Answer
Answer:
It is 23
Step-by-step explanation:
BC= FE
(x-4)=19
Therefore x= 23