Answer:
y = x*(6 feet/1 fathom)
Step-by-step explanation:
We know the relation:
1 fathom = 6 feet.
We can write:
1 = (6 feet/1 fathom)
Now, remember that any number multiplied by 1 does not change.
Then suppose that we have a measure of 3 fathoms, then:
3 fathoms = (3 fathoms)*1
= (3 fathoms)*((6 feet/1 fathom)) = (3 fathoms/1 fathom)*(6feet)
= 3*(6 feet) = 18 feet.
So we changed the units by multiplying the original measure by (6 feet/1 fathom)
Then, if x is the depth of water in fathoms and y is the depth of the water in feet, we can write:
y = x*(6 feet/1 fathom)
Answer:
The first graph.
Step-by-step explanation:
I can see 3 graphs. The first one is a cubic equation.
The angle sum of quadrilateral is 360 so just 360 - 120- 48 - 92 so the fourth angle should be 100°
the area of triangle is base X height /2 so the answer is 6 x 8 /2 = 24
Answer:
$23,700
Step-by-step explanation:
The compound interest formula can be helpful for this. Fill in the given values and solve for the unknown.
FV = P(1 +r/n)^(nt)
where r is the annual interest rate, n is the number of times interest is compounded in a year, t is the number of years, P is the amount invested, and FV is the future value of that investment.
$27,000 = P(1 +0.022/365)^(365·6) = 1.1411037P
P ≈ $23,700
Recall what a parallel line is; two lines that are parallel are defined as having the same gradient or slope. Consider a line:
y = mx + b
If we want to find a certain line that is / parallel / to the original line passing through an arbitrary point (x₁, y₁), it is useful to understand the point-gradient or point-slope formula.
The gradient to the line y = mx + b is simply m. So, any parallel line to y = mx + b will have the same gradient. Examples include: y = mx + 1, y = mx + 200, y = mx + g
All we need to know, now, is to identify what specific line hits the desired point. Well, the point-gradient formula can help with that. Recall that the point-gradient formula is:
y - y₀ = m(x - x₀), where (x₀, y₀) is the point of interest.
Hence, it is useful to use the point-slope formula when asked for a point and a set of parallel lines to the original line.
