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Answer:
the number of seconds that you and your friend would be have the similar distance from the starting line is 20 seconds
Step-by-step explanation:
The computation of the number of seconds that you and your friend would be have the similar distance from the starting line is shown below:
As we know that
Speed = Distance ÷ Time
SO,
Time = Distance ÷ speed
= 10 meters ÷ difference in speed
= 10 meters ÷ (6 meters per second - 5.5 meters per second)
= 10 meters ÷ 0.5 meters per second
= 20 seconds
hence, the number of seconds that you and your friend would be have the similar distance from the starting line is 20 seconds
Step 1
<u>Find the value of s</u>
we know that
In a Rhombus all sides are congruent
so
equate AB and CD
Combine like term
<u>The answer Part a) is</u>
the value of s is 
Step 2
<u>Find the value of side AB</u>
substitute the value of s
Remember that the sides are congruent
therefore
<u>the answer Part b) is</u>
The length of the side BC is 
Answer:
-2 and 21/50
Step-by-step explanation:
PEMDAS says that paranthases go first, so we solve 2 and 1/5 minus 33/12. 2 and 1/5 simplifies to the improper fraction, 11/5. Then we find a common denominater between 11/5 and 33/12 to get 60. 11/5=132/60, and 33/12=165/60. (132/60)-(165/60)=-33/60. Then we multipl that by 4 and 2/5, which can simplify to the improper fraction, 22/5. (22/5)*(-33/60) is -726/300, and simplifies to -2 and 21/50. Hope this helps!
