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Nastasia [14]
3 years ago
6

What conclusions can you draw from the distances that you recorded in Question 7?

Mathematics
2 answers:
Ipatiy [6.2K]3 years ago
8 0

Answer:

Step-by-step explanation: What was question 7

lisov135 [29]3 years ago
4 0

Answer:  If corresponding vertices on an image and a preimage are connected with line segments, the line segments are divided equally by the line of reflection. That is, the perpendicular distance from the line of reflection to either of the corresponding vertices is the same. Line  is a perpendicular bisector of the connecting line segments.

Step-by-step explanation:

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The coordinates A(2, 1), B(7, 1), C(2, 4) form what type of polygon?
Digiron [165]

Step-by-step explanation:

Slope \:  of \:  AB =  \frac{1 - 1}{7 - 2}  =  \frac{0}{5}  = 0 \\  \\ Slope \:  of \:  BC =  \frac{4 - 1}{2 -  7}  =  \frac{3}{ - 5}  =  - \frac{3}{ 5}   \\  \\  \because \: Slope \:  of \:  AB \neq \: Slope \:  of \:  BC \\  \\  \therefore \: given \: points \: are \: non - collinear. \\

Hence, coordinates A(2, 1), B(7, 1), C(2, 4) form a triangle.

6 0
4 years ago
Read 2 more answers
Help with this I gave all my points plzzz
Delvig [45]

Answer:

y = 5 and slope = -1/3

Step-by-step explanation:

See pictures for full explanation.

6 0
3 years ago
When an article is sold for Rs 23, there is profit.
Svet_ta [14]

Answer:

Cost price = R.S 20

Sales price = R.S 22

Step-by-step explanation:

Given:

Sales price of an article = R.S 23

Profit = 15%

Find:

Cost price

Sales price if profit is 10%

Computation:

Profit% = [(Sales price - Cost price) / Cost price]100

15 = [(23-cp)/cp]100

15cp = 2,300 - 100cp

115cp = 2,300

Cost price = R.S 20

Sales price if profit is 10%

Sales price = Cost price + Profit

Sales price = 20 + 10%[20]

Sales price = 20 + 2

Sales price = R.S 22

3 0
3 years ago
Consider the following sets of matrices: M2(R) is the set of all 2 x 2 real matrices; GL2(R) is the subset of M2(R) with non-zer
defon

Answer:

Step-by-step explanation:

REcall the following definition of induced operation.

Let * be a binary operation over a set S and H a subset of S. If for every a,b elements in H it happens that a*b is also in H, then the binary operation that is obtained by restricting * to H is called the induced operation.

So, according to this definition, we must show that given two matrices of the specific subset, the product is also in the subset.

For this problem, recall this property of the determinant. Given A,B matrices in Mn(R) then det(AB) = det(A)*det(B).

Case SL2(R):

Let A,B matrices in SL2(R). Then, det(A) and det(B) is different from zero. So

\text{det(AB)} = \text{det}(A)\text{det}(B)\neq 0.

So AB is also in SL2(R).

Case GL2(R):

Let A,B matrices in GL2(R). Then, det(A)= det(B)=1 is different from zero. So

\text{det(AB)} = \text{det}(A)\text{det}(B)=1\cdot 1 = 1.

So AB is also in GL2(R).

With these, we have proved that the matrix multiplication over SL2(R) and GL2(R) is an induced operation from the matrix multiplication over M2(R).

7 0
3 years ago
Find the curved surface area of a cylinder diameter 12cm and length 30cm (fast plz) ​
Effectus [21]

Answer:

solution:-

diameter of a cylinder (d) = 12 cm

length(h) = 30 cm

curved surface area of cylinder (csa) = ?

we know that ,

therefore , csa of cylinder = 2πrh

r = d/2

or, r = 12/2= 6 cm

Then, csa if cylinder = 2 ×22/7×30

= 2×22×30/7

= 1320/7

= 188.57 Square cm Ans,......

7 0
3 years ago
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