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Kazeer [188]
2 years ago
10

Find two consecutive intergers whose sum is 45

Mathematics
2 answers:
77julia77 [94]2 years ago
5 0

Answer:

n + ( n+1 ) = 45

Step-by-step explenation:

2n+1=45

2n = 45 - 1

2n = 44

n = 44/2

n=22

22 and 23

andriy [413]2 years ago
4 0

Answer:

The reqd. integers are  

22  and 23

Step-by-step explanation:

Since consecutive integers are required, we let them be  

x  and  x + 1 . These add to  45

, we have,  x + x + 1=45

⇒ 2x +1= 45

⇒2 x= 44

⇒ x= 22  and ,  s o  x + 1 = 23

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Whats the value of 8:3 ?
umka2103 [35]

Answer:

As a mixed number, 8/3 is equal to 2-2/3.

Step-by-step explanation:

6 0
2 years ago
What is the value of x in the equation 1/5x – 2/3y = 30, when y = 15?
Maksim231197 [3]
X=200
2/3 of 15 is 10 make that negative add it to the other side 1/5x = 40 and then multiply 40 by 5 to get your answer
Check 
1/5 of 200 is 40 - 10 = 30
40-10=30
30=30
6 0
3 years ago
If k(x) = 2x² -3.Vx, then k(9) is
Alexus [3.1K]

Answer:

159

Step-by-step explanation:

k (9) = (2 * 9^{2}) - 3

= (2 * 81) - 3

= 162 - 3

= 159

8 0
2 years ago
If the ratio of red socks to blue socks is 1:6, how many red socks would I have if I had 24 blue socks?
svetoff [14.1K]

Answer:4

Step-by-step explanation:

1:6

Divide 6 by 24

you will get 4

Times your answer by 1 and then u will get your final answer

3 0
3 years ago
Read 2 more answers
If f(x) = 16x – 30 and g(x) = 14x – 6, for which value of x does (f – g)(x) = 0?
andre [41]

The value of the x will be 12. The value of the x is obtained from the condition,(f – g)(x) = 0

<h3>What exactly is a function?</h3>

A function is a statement, rule, or law that specifies the connection between two variables. Functions are common in mathematics and are required for the formulation of physical connections.

Given function;

f(x) = 16x – 30

g(x) = 14x – 6

⇒(f – g)(x) = 0

⇒(16x – 30)-(14x – 6)=0

⇒16x-30-14x+6=0

⇒2x-24=0

⇒x=24/2

⇒x=12

Hence, the value of the x will be 12.

To learn more about the function, refer to:

brainly.com/question/5245372

#SPJ1

8 0
1 year ago
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