Distance is calculated by the square root of (x2-x1)^2 + (y2-y1)^2
We simply substitute the values into this formula
Square root of (3--5)^2 + (0-1)^2
Which is 8
Use pythagoras
d = √(Δx² + Δy²)
d = √(12-2)² + (9-4)²
d = √(10² + 5²)
d = √(100 + 25)
d = √125
d = 5√5
d = 5 × 2.236
d = 11.18
The nearest tenth is 11.2, so the distance is near to 11.2
Answer:
See below
Step-by-step explanation:
The function 
oscillates between -1 and 1, so the range is 
.
Answer:
5/16
Step-by-step explanation:
In 5/2 the time, we expect that 5/2 × 1/8 = 5/16 of the test will be complete.
_____
5/2 × (2/5 h) = 1 h
Answer:
8.75!
Step-by-step explanation:
the answer is x-2.5=6.25
6.25+2.50=8.75
