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2 years ago

CAN SOMEONE JUST PLEASE ANSWER THIS ASAP FOR BRAINLIEST

Mathematics

1 answer:

AVprozaik [17]2 years ago

6 0

$x^2 - 9x + 20=x^2-4x-5x+20=x(x-4)-5(x-4)=(x-5)(x-4)$

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Hello, I really need help with this!

yuradex [85]

1. Given
2. Definition of Supplementary Angles
3. First Substitution
4. Subtraction property of Equality
5. Second Substitution
6. Exterior Side in Opposite Rays
7. If corresponding angles are equal, then lines are parallel

5 0

3 years ago

A set of equations is shown above. Which method eliminates one of the variables? A) Multiply equation A by -1/3 and add the resu

Paraphin [41]

Answer:

Step-by-step explanation:

Multiplying Equation A by (1/3) and adding the result to Equation B will do the trick. Let's actually solve the problem!

Equation A: (5/3)x + 3y = 12

Equation B: 4x - 3y = 8

---------------------------

(5/3 + 12/3)x = 15 Note how this has eliminated the variable

(17/3)x = 15 y.

x = (3/17)(15)

8 0

3 years ago

A triangle has an area of 54 square inches the height of the triangle is 12 inches what is the length of the base of the triangl

prohojiy [21]

Answer:

The base of the triangle = 9inches

Step-by-step explanation:

Explanation:-

The area of the triangle = $\frac{1}{2} bh$ square units

Given area of the triangle(A) = 54 square inches

Given the height of the triangle (h) = 12 inches

now equating $\frac{1}{2} b h = 54$

$\frac{1}{2} b (12) = 54$

now simplification, we get

6 b = 54

Dividing '6' on both sides, we get

b = 9

The base of the triangle = 9 inches

Conclusion:-

The base of the triangle = 9 inches

6 0

3 years ago

Explain how to multiply the following whole numbers 21 x 14

Lesechka [4]

Answer:

$\begin{matrix}\space\space&\textbf{2}&\textbf{1}\\ \times \:&1&\textbf{4}\end{matrix}$

________

$\frac{\begin{matrix}\space\space&\textbf{0}&8&4\\ +&\textbf{2}&1&0\end{matrix}}{\begin{matrix}\space\space&\textbf{2}&9&4\end{matrix}}$

Step-by-step explanation:

Given

$21\:\times \:14$

Line up the numbers

$\begin{matrix}\space\space&2&1\\ \times \:&1&4\end{matrix}$

Multiply the top number by the bottom number one digit at a time starting with the ones digit left(from right to left right)

Multiply the top number by the bolded digit of the bottom number

$\begin{matrix}\space\space&\textbf{2}&\textbf{1}\\ \times \:&1&\textbf{4}\end{matrix}$

Multiply the bold numbers: 1×4=4

$\frac{\begin{matrix}\space\space&2&\textbf{1}\\ \times \:&1&\textbf{4}\end{matrix}}{\begin{matrix}\space\space&\space\space&4\end{matrix}}$

Multiply the bold numbers: 2×4=8

$\frac{\begin{matrix}\space\space&\textbf{2}&1\\ \times \:&1&\textbf{4}\end{matrix}}{\begin{matrix}\space\space&8&4\end{matrix}}$

Multiply the top number by the bolded digit of the bottom number

$\frac{\begin{matrix}\space\space&\textbf{2}&\textbf{1}\\ \times \:&\textbf{1}&4\end{matrix}}{\begin{matrix}\space\space&8&4\end{matrix}}$

Multiply the bold numbers: 1×1=1

$\frac{\begin{matrix}\space\space&\space\space&2&\textbf{1}\\ \space\space&\times \:&\textbf{1}&4\end{matrix}}{\begin{matrix}\space\space&\space\space&8&4\\ \space\space&\space\space&1&\space\space\end{matrix}}$

Multiply the bold numbers: 2×1=2

$\frac{\begin{matrix}\space\space&\space\space&\textbf{2}&1\\ \space\space&\times \:&\textbf{1}&4\end{matrix}}{\begin{matrix}\space\space&\space\space&8&4\\ \space\space&2&1&\space\space\end{matrix}}$

Add the rows to get the answer. For simplicity, fill in trailing zeros.

$\frac{\begin{matrix}\space\space&\space\space&2&1\\ \space\space&\times \:&1&4\end{matrix}}{\begin{matrix}\space\space&0&8&4\\ \space\space&2&1&0\end{matrix}}$

adding portion

$\begin{matrix}\space\space&0&8&4\\ +&2&1&0\end{matrix}$

Add the digits of the right-most column: 4+0=4

$\frac{\begin{matrix}\space\space&0&8&\textbf{4}\\ +&2&1&\textbf{0}\end{matrix}}{\begin{matrix}\space\space&\space\space&\space\space&\textbf{4}\end{matrix}}$

Add the digits of the right-most column: 8+1=9

$\frac{\begin{matrix}\space\space&0&\textbf{8}&4\\ +&2&\textbf{1}&0\end{matrix}}{\begin{matrix}\space\space&\space\space&\textbf{9}&4\end{matrix}}$

Add the digits of the right-most column: 0+2=2

$\frac{\begin{matrix}\space\space&\textbf{0}&8&4\\ +&\textbf{2}&1&0\end{matrix}}{\begin{matrix}\space\space&\textbf{2}&9&4\end{matrix}}$

Therefore,

$\begin{matrix}\space\space&\textbf{2}&\textbf{1}\\ \times \:&1&\textbf{4}\end{matrix}$

________

$\frac{\begin{matrix}\space\space&\textbf{0}&8&4\\ +&\textbf{2}&1&0\end{matrix}}{\begin{matrix}\space\space&\textbf{2}&9&4\end{matrix}}$

6 0

3 years ago

The figure shows a gas tank in the form of a rectangular prism that is 40% full. How many more gallons of gas will it take to fi

Ira Lisetskai [31]

Answer:

10.8 gallons

Step-by-step explanation:

First change everything to inches:

2.75 ft = 33 in

1.5 ft = 18 in

Volume of tank = lwh = (33)(18)(7) = 4158 in³

The tank is 40% full, so only 60% is need to fill it. To find 60%, multiply 4158 by 0.6 = 2494.8 in³

Now find out how much 2494.8 in³ is in gallons:

231 in³ = 1 gallon

1 in³ = 1/231 gallons

2494.8 = (1/231)(2494.8) gallons = 10.8 gallons

7 0

3 years ago