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Levart [38]
3 years ago
11

Is x+3 a factor of x^4-2x^3-15x^2-14x-12

Mathematics
1 answer:
Nookie1986 [14]3 years ago
7 0
Use synthetic division here, if you know it.  Use -3 as divisor and use the coefficients 1  -2  -15  -14  -12.  If there is no remainder, then x+3 is a factor of the given polynomial.

      _____________________
-3  /  1   -2   -15   -14   -12
             -3     15      0    42
      ---------------------------------
         1   -5      0    -14    30

There's a non-zero remainder:  30.  This means that the polynomial has the value 30 when x = -3, and that (x+3) is NOT a factor of the poly.
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sergiy2304 [10]
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3 years ago
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photoshop1234 [79]

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Step-by-step explanation:

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7 0
3 years ago
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allochka39001 [22]

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Step-by-step explanation:

8 0
3 years ago
Find the pattern and use it to list the next two terms in the sequence.
lidiya [134]

Answer:

Step-by-step explanation:

a₁ = -3 = (-1)¹×3

a₂ = 6 = (-1)²×2×3

a₃ = -28 = (-1)³×2²×7

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a₆ = 2160 = (-1)⁶×2⁴×3³×5

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8 0
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A(-3,2) B(5,-4) midpoint is (1,-1)
lesya [120]
CHECK:\\\\the\ midpoint\ AB:\left(\frac{-3+5}{2};\ \frac{2-4}{2}\right)=\left(\frac{2}{2};\ \frac{-2}{2}\right)=(1;-1)\\-------------------------------\\C(x;\ y)\\\\the\ midpoint\ AC:\left(\frac{-3+x}{2};\ \frac{2+y}{2}\right)\\\\B\ is\ the\ midpoint\ AC\ then:\\\\\frac{-3+x}{2}=5\ and\ \frac{2+y}{2}=-4\\\\-3+x=10\ and\ 2+y=-8\\\\x=10+3\ and\ y=-8-2\\\\x=13\ and\ y=-10\\\\Solution:C(13;-10).
7 0
3 years ago
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