All categories

3 years ago

PLEASE HELP ME HURRY

Mathematics

1 answer:

Ymorist [56]3 years ago

8 0

Answer:

6/5

Step-by-step explanation:

You might be interested in

For allnâˆˆNâ‰¥1(sonâ‰¥1), and usingweakinduction, prove that:nâˆ‘i=1i3=[n(n+ 1)2]2Note that this result means that the sum of t

kirill [66]

Answer:

Step-by-step explanation:

hello,

the question is not really clear. i believe the intended equation would be

$\sum_{k=1}^{k=n} k^3=\frac{(n(n+1))}{4}$

please check the attached file for the step by step proof.

8 0

2 years ago

Help plzz! True or False? <br> -15 is a solution for -8x = 125

dmitriy555 [2]

Answer:

false, it doesn't equal 125

4 0

2 years ago

Read 2 more answers

Express the product of (1/5x + 1) and (1/6x + 5/4) as a trinomial in simplest form

Greeley [361]

$(\frac{1}{5}x+1)(\frac{1}{6}x+\frac{5}{4})$

Use distributive property to remove the parentheses:

$(a+b)(c+d)=ac+ad+bc+bd$ $\begin{gathered} =\frac{1}{5}x*\frac{1}{6}x+\frac{1}{5}x*\frac{5}{4}+1*\frac{1}{6}x+1*\frac{5}{4} \\ \\ Multiplication\text{ }of\text{ }fractions: \\ \frac{a}{b}*\frac{c}{d}=\frac{a*c}{b*d} \\ \\ =\frac{1}{30}x^2+\frac{5}{20}x+\frac{1}{6}x+\frac{5}{4} \\ \\ =\frac{1}{30}x^2+\frac{1}{4}x+\frac{1}{6}x+\frac{5}{4} \\ \\ Addition\text{ }of\text{ }fractions: \\ \frac{a}{b}+\frac{c}{d}=\frac{ad+bc}{bd} \\ \\ =\frac{1}{30}x^2+(\frac{6x+4x}{24})+\frac{5}{4} \\ \\ =\frac{1}{30}x^2+\frac{10}{24}x+\frac{5}{4} \\ \\ Simplify: \\ =\frac{1}{30}x^2+\frac{5}{12}x+\frac{5}{4} \end{gathered}$ Then, the product in the simplest form is: $\frac{1}{30}x^2+\frac{5}{12}x+\frac{5}{4}$

8 0

1 year ago

Convert the improper fraction to a mixed number. 17/3=

san4es73 [151]

Answer:

17/3 = 5 2/3

Step-by-step explanation:

3 goes into 17 5 times, the remaining numbers are 2.

5 0

3 years ago

GUVING BRANLISEST !!!!!’

quester [9]

Answer:

2, 5, 6

Step-by-step explanation:

from top to bottom, it's the second, fifth, and sixth

6 0

3 years ago