d = distance between the two cities
v₁ = average speed while going from chicago to kansas city = 440 knots
t₁ = time taken to travel distance going from chicago to kansas city
time taken to travel distance going from chicago to kansas city is given as
t₁ = d/v₁
t₁ = d/440 eq-1
v₂ = average speed while going from kansas city to chicago = 110 knots
t₂ = time taken to travel distance going from kansas city to chicago
time taken to travel distance going from kansas city to chicago is given as
t₂ = d/v₂
t₂ = d/110 eq-2
Given that :
t₂ = t₁ + 3
using eq-1 and eq-2
(d/110) = (d/440) + 3
d = 440
This is an exam! You are not supposed too cheat!
>:O
A: Slope-intercept form: y = 2 x − 1 Point-slope form: y − 7 = 2 ⋅ ( x − 4 )
B: Slope-intercept form: y = 4 x + 7 Point-slope form: y + 1 = 4 ⋅ ( x + 2 )
C: Slope-intercept form: y = 1/2 x − 8 Point-slope form: y + 4 = 1/2 ⋅ ( x − 8 )
-x^2+2x+3=x^2-2x+3 add x^2 to both sides
2x+3=2x^2-2x+3 subtract 2x from both sides
3=2x^2-4x+3 subtract 3 from both sides
2x^2-4x=0 factor
2x(x-2)=0
So x=0 and 2
