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motikmotik
3 years ago
5

Answer number 3 in the picture pls! I really need the help

Mathematics
1 answer:
kakasveta [241]3 years ago
3 0
2(5x+4) I think this is the answer to your question
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Round 954 to the nearest hundred
Alla [95]

Answer:

Step-by-step explanation:

1000

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4 years ago
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"Use the following information to answer the question. The mean age of lead actresses from the top ten grossing movies of 2010 w
julia-pushkina [17]

Answer:

a) 10.6; 48.7; within

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean = 29.6

Standard deviation = 6.35

"According to the Empirical Rule, the ages of nearly all lead actresses will be between______________and_____________ years.

Nearly all(99.7%) will be within 3 standard deviations from the mean.

So from 29.6 - 3*6.35 = 10.6 years to 29.6 + 3*6.35 = 48.7 years.

Anna was 11-years old, so she was within this range.

So the correct answer is

a) 10.6; 48.7; within

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3 years ago
What the area of this shape
Orlov [11]

Answer: The Answer is 150.

I don't know if this is the right answer

5 0
2 years ago
Rewrite each expression as a polynomial in standard form: x^2-5x+6 ÷ x-3 + x^3-1 ÷ x-1
iragen [17]

Answer:

So in standard form equation will be x^2+2x-1

Step-by-step explanation:

We have given expression \frac{x^2-5x+6}{x-3}+\frac{x^3-1}{x-1}

Let first we solve first part of the expression

So \frac{x^2-5x+6}{x-3}=\frac{x^2-3x-2x+6}{x-3}=\frac{(x-3)(x-2)}{x-3}=x-2

Now second part \frac{x^3-1}{x-1}

We know the algebraic identity a^3-b^3=(a-b)(a^2+ab+b^2)

So by using this identity

\frac{x^3-1}{x-1}=\frac{(x-1)(x^2+x+1)}{x-1}=x^2+x+1

Now adding first and second part

x-2+x^2+x+1=x^2+2x-1

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4 0
3 years ago
If x=3m-4 and y=6-m, which of the following expresses y in terms of x
coldgirl [10]

Answer:

What you want to do is solve for m in whichever equation it's easier to so in, then substitute that in to the other equation. For instance:

X=3m-4

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Solve the 2nd equation to get m=6-y

Plug that into the first equation to get x=3(6-y)-4

X=18-3y-4

X-14=-3y

14-x=3y

Y=(14-x)/3

6 0
3 years ago
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