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kobusy [5.1K]
3 years ago
10

Aproximately 1 in 28 people of ashkenazi jewish descent are tay-sachs carrier. ... from this population, what is the probability

neither is tay-sachs carrier?
Mathematics
1 answer:
zmey [24]3 years ago
8 0
If we randomly pick two persons from the population, each one will have a probability of 1-1/28=27/28 of being a non-carrier.
Thus for neither to be non-carrier, the probability is the product of the individual probabilities since the picks are assumed independent (with a large enough population).

Probability = (27/28)*(27/28) = 729/784 
or approximately 0.930
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katen-ka-za [31]
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77julia77 [94]

Given:

A line passes through the points (2,-1) and (1,-5).

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The line passes through the points (2,-1) and (1,-5). So, the equation of the line is

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