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Bond [772]
3 years ago
9

La ecuación de la recta que pasa por los puntos (2,-1) y (1,-5) es:

Mathematics
1 answer:
77julia77 [94]3 years ago
5 0

Given:

A line passes through the points (2,-1) and (1,-5).

To find:

The equation of the line.

Solution:

If a line passes through the two points, then the equation of the line is

y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)

The line passes through the points (2,-1) and (1,-5). So, the equation of the line is

y-(-1)=\dfrac{-5-(-1)}{1-2}(x-2)

y+1=\dfrac{-5+1}{-1}(x-2)

y+1=\dfrac{-4}{-1}(x-2)

y+1=4(x-2)

Using distributive property, we get

y+1=4(x)+4(-2)

y+1=4x-8

Subtract 1 from both sides.

y+1-1=4x-8-1

y=4x-9

Therefore, the correct option is B.

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Step-by-step explanation:

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Answer:

First option:  3x^2-5x=-8

Second option: 2x^2=6x-5

Fourth option: -x^2-10x=34

Step-by-step explanation:

Rewrite each equation in the form ax^2+bx+c=0 and then use the Discriminant formula for each equation. This is:

D=b^2-4ac

1) For 3x^2-5x=-8:

 3x^2-5x+8=0

Then:

D=(-5)^2-4(3)(8)=-71

Since D this equation has no real solutions, but has two complex solutions.

2) For 2x^2=6x-5:

 2x^2-6x+5=0

Then:

D=(-6)^2-4(2)(5)=-4

Since D this equation has no real solutions, but has two complex solutions.

3) For 12x=9x^2+4:

 9x^2-12x+4=0

Then:

D=(-12)^2-4(9)(4)=0

Since D=0 this equation has one real solution.

4) For -x^2-10x=34:

 -x^2-10x-34=0

Then:

D=(-10)^2-4(-1)(-34)=-36

Since D, this equation has no real solutions, but has two complex solutions.

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Step-by-step explanation:

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