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Bond [772]
3 years ago
9

La ecuación de la recta que pasa por los puntos (2,-1) y (1,-5) es:

Mathematics
1 answer:
77julia77 [94]3 years ago
5 0

Given:

A line passes through the points (2,-1) and (1,-5).

To find:

The equation of the line.

Solution:

If a line passes through the two points, then the equation of the line is

y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)

The line passes through the points (2,-1) and (1,-5). So, the equation of the line is

y-(-1)=\dfrac{-5-(-1)}{1-2}(x-2)

y+1=\dfrac{-5+1}{-1}(x-2)

y+1=\dfrac{-4}{-1}(x-2)

y+1=4(x-2)

Using distributive property, we get

y+1=4(x)+4(-2)

y+1=4x-8

Subtract 1 from both sides.

y+1-1=4x-8-1

y=4x-9

Therefore, the correct option is B.

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Answer:

<u>The value of x is 11 and CE = 40 and AC = 60</u>

Step-by-step explanation:

Δ ΑΒC ≅ Δ EDS, therefore we have that:

24 / 36 = 3x + 7 / 6x - 6

Solving for x,

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<u>The value of x is 11 and CE = 40 and AC = 60</u>

3 0
3 years ago
Where should Jenna insert parentheses to make the equation true? 2 + 4.5+ 1 = 26​
swat32
The best thing I can think of is
((2)(4))(.5+1)=(2)(6)
because (2*4)(1.5)= 8*1.5
= 12
and 2*6 =12
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I hope this is right and I hope it helps!
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sukhopar [10]

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About 34 workers

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If the graph f(x)= 9x^2+37x+41/3x+5 has an oblique asymptote at y=3x+k what is the value of k
ira [324]

Answer:

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Step-by-step explanation:

The oblique asymptote of

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