SOH CAH TOA
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Sin D = 13 sqrt3/26 = 0.76
Sin E = 13/26 = 0.47
Cos D = 13/26 = 0.87
Cos E = 13 sqrt3/26 = 0.64
Answer:
C.
Step-by-step explanation:
Hope this Helps you !
Answer: 7 and 8
<u>Step-by-step explanation:</u>
Let x represent the first number, then x + 1 is the other number.
(x)² + (x + 1)² = 113
x² + x² + 2x + 1 = 113 <em>expanded (x + 1)²</em>
2x² + 2x + 1 = 113 <em>added like terms</em>
2x² + 2x - 112 = 0 <em>subtracted 113 from both sides</em>
x² + x - 56 = 0 <em> divided both sides by 2</em>
(x + 8) (x - 7) = 0 <em>factored polynomial</em>
x + 8 = 0 x - 7 = 0 <em>applied zero product property</em>
x = -8 x = 7 <em> solved for x</em>
↓
not valid since the restriction is that x > 0 <em>(a positive number)</em>
So, x = 7 and x + 1 = (7) + 1 = 8
I would say it’s c.
D is wrong cause definitions are proven right all the time.
B is wrong because a definition is not an arrangement of deductions
A is wrong because it says that the statement is not defined when it is.
Answer:
15, -26
Step-by-step explanation:
The <em>generic solution</em> to a "sum and difference" problem can be found easily. Let "a" and "b" represent the numbers you seek, and let "s" and "d" represent their sum and difference:
a + b = s
a - b = d
Adding these two equations tells you ...
2a = s + d
a = (s + d)/2 . . . . . . divide by the coefficient of a
You can find "b" several different ways. One way is to subtract the second equation from the first:
2b = s - d
b = (s - d)/2 . . . . . . divide by the coefficient of b
So, the second number can be found from any of ...
- b = s - a
- b = a - d
- b = (s - d)/2
____
For the numbers given here, s=-11, d=41, the two numbers are ...
a = (-11 +41)/2 = 15
b = -11 -15 = -26
The two numbers are 15 and -26.
