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4vir4ik [10]
3 years ago
15

Gabby is going to see Disney on ice there are 12 people going to Disney on ice. Gabby pays $24.50 for each ticket to Disney on i

ce. Gabby is also buying 5 Disney light sabers. Gabby is charged a total of 372.75 for tickets and light sabers. What was the price of each light saber?
Mathematics
1 answer:
algol [13]3 years ago
7 0
First, you have to multiply 12×24.50=$360.00. Next, you have to subtract 372.75-360.00=12.75. Then, you have to divide 12.75÷5=$2.55. So in conclusion, each lightsaber costs $2.55.
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Answer:

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Step-by-step explanation:

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5 0
3 years ago
Please help me with those question please help with out number 1
alina1380 [7]

Answer:

1) For each value of x, a value of y is increased by 5.

x = 0, y = 5

x = 1, y = 10

x = 2, y = 15

x = 3, y = 20

------------------------------------------------------------------------------------------

2) For each two values of x, a value of y is increased by 10.

x = 0, y = -2

x = 2, y = 8

x = 4, y = 18

x = 6, y = 28

-------------------------------------------------------------------------------------------

3)

x = 0, y = 1

x = 1, y = \frac{7}{5}

x = 5, y = 3

x = 10, y = 5

-------------------------------------------------------------------------------------------------

4)

x = 0, y = 2

x = 1, y = 17

x = 2, y = 32

x = 5, y = 77

Step-by-step explanation:

This is as easy as replacing x for the actual value show on the table.

1)

y=5x+5

When x = 0, y = ?

y=5(0)+5\\y=0+5\\y=5

When x = 1, y = ?

y=5(1)+5\\y=5+5\\y=10

When x = 2, y = ?

y=5(2)+5\\y=10+5\\y=15

When x = 3, y = ?

y=5(3)+5\\y=15+5\\y=20

-------------------------------------------------------------------------------------------------------

2)

y=5x-2

When x = 0, y = ?

y=5(0)-2\\y=0-2\\y=-2

When x = 2, y = ?

y=5(2)-2\\y=10-2\\y=8

When x = 4, y = ?

y=5(4)-2\\y=20-2\\y=18

When x = 6, y = ?

y=5(6)-2\\y=30-2\\y=28

----------------------------------------------------------------------------------------------------

3)

y=\frac{2}{5}x +1

When x = 0, y = ?

y=\frac{2}{5}(0) +1

y=0 +1\\y=1

When x = 1, y = ?

y=\frac{2}{5}(1) +1\\y=\frac{2}{5} +1

y=\frac{2}{5}+1(\frac{5}{5})\\ y=\frac{2}{5}+\frac{5}{5}  \\y=\frac{7}{5}

When x = 5, y = ?

y=\frac{2}{5}(5) +1\\y=2+1\\y=3

When x = 10, y = ?

y=\frac{2}{5}(10) +1\\y=2(2) +1\\y=4+1\\y=5

-------------------------------------------------------------------------------------------------

4)

y=15x+2

When x = 0, y = ?

y=15(0)+2\\y=0+2\\y=2

When x = 1, y = ?

y=15(1)+2\\y=15+2\\y=17

When x = 2, y = ?

y=15(2)+2\\y=30+2\\y=32

When x = 5, y = ?

y=15(5)+2\\y=75+2\\y=77

4 0
3 years ago
Read 2 more answers
John sells hamburgers ($3) and cheeseburgers ($3.50). One afternoon he sells a total of 24 burger for $79. How many of these wer
ankoles [38]

John sold 10 hamburgers and 14 cheeseburgers.

Step-by-step explanation:

Given,

Cost of one hamburger = $3

Cost of one cheeseburger = $3.50

Total burgers sold = 24

Total revenue earned = $79

Let,

Number of hamburgers sold = x

Number of cheeseburgers sold = y

According to given statement;

x+y=24   Eqn 1

3x+3.50y=79    Eqn 2

Multiplying Eqn 1 by 3

3(x+y=24)\\3x+3y=72\ \ \ Eqn\ 3

Subtracting Eqn 3 from Eqn 2

(3x+3.50y)-(3x+3y)=79-72\\3x+3.50y-3x-3y=7\\0.50y=7

Dividing both sides by 0.50

\frac{0.50y}{0.50}=\frac{7}{0.50}\\y=14

Putting y=14 in Eqn 1

x+14=24\\x=24-14\\x=10

John sold 10 hamburgers and 14 cheeseburgers.

Keywords: linear equation, elimination method

Learn more about elimination method at:

  • brainly.com/question/13070361
  • brainly.com/question/13084321

#LearnwithBrainly

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