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3 years ago

14

Given the linear equation 2x+y=6, perform the necessary operations to put the equation into the proper general form. Include the

entire process for establishing the general form of the equation and the general form.

1 answer:

e-lub [12.9K]3 years ago

8 0

Answer:

y = -2x + 6

Step-by-step explanation:

2x + y = 6

Subtract 2x both sides

2x + y - 2x = 6 - 2x

y = -2x + 6

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A pair of shoes costs three times as much as a scarf. The total cost of 1 pair of shoes and 1 scarf is $32. If s represents the

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3s+s=32

I did it on TTM and it was correct ^^

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4 years ago

What is the measure of 1?

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3 years ago

Read 2 more answers

What are the coordinates of the turning point for the function f(x) = (x + 2)3 − 4?

AnnZ [28]

Answer:A

Step-by-step explanation:

Given

$F(x)=(x+2)^3-4$

Turning Point is the point where the graph changes its nature i.e. either increasing to decreasing or decreasing to increasing

to find turning point

$F'(x)=3(x+2)^2+0$

For critical point

F'(x)=0

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thus

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3 years ago

A small junior college had an enrollment of 7,843 students in the year 1990 and 8,793 students in the year 2000. Let x=0 represe

abruzzese [7]

Correct answer is: (0,7843) and (10,8793)

Solution:-

Given that a junior college has an enrollment of 7843 students in 1990 and 8793 students in year 2000.

We have to write this data as (x,y) .

Where x= years after 1990 and y=number of students enrolled.

Since in 1990, 7843 students enrolled, x = 1990-1990=0

And y=7843.

Hence one ordered pair is (0,7843).

Let us find the years after 1990 for 2000 = 2000-1990 =10

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3 years ago

Two passenger train, A and B, 450 km apart, star to move toward each other at the same time and meet after 2hours.

likoan [24]

Let $v$ be the speed of train A, and let's set the origin in the initial position of train A. The equations of motion are

$\begin{cases}s_A(t) = vt\\s_B(t) = -\dfrac{8}{7}vt+450\end{cases}$

where $s_A,\ s_B$ are the positions of trains A and B respectively, and t is the time in hours.

The two trains meet if and only if $s_A=s_B$ , and we know that this happens after two hours, i.e. at $t=2$

$\begin{cases}s_A(2) = 2v\\s_B(2) = -\dfrac{16}{7}v+450\end{cases}\implies 2v = -\dfrac{16}{7}v+450$

Solving this equation for v we have

$2v = -\dfrac{16}{7}v+450 \iff \dfrac{30}{7}v=450 \iff v=\dfrac{450\cdot 7}{30} = 105$

So, train A is travelling at 105 km/h. This implies that train B travels at

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5 0

3 years ago